How to transform List of tuples to multiple tuples?

Question

I want to have a method that builds up query parameters for def withQueryString(parameters: (String, String)*): WSRequest. In particular, I have the following method:

def toParams: Seq[(String, String)] = {
  val params = List(
    ("firstName" -> "john"),
    ("lastName" -> "doe"),
    ("age" -> "35"),
    ("ssnr" -> "1234")
  )
  params
}

The problem is that the method withQueryString requires (String, String)* instead of Seq[(String, String)]. How can I make this conversion?

Possible duplicate of [How to pass scala Array into scala vararg method?](http://stackoverflow.com/questions/31064753/how-to-pass-scala-array-into-scala-vararg-method) — Tzach Zohar, Oct 09 '16 at 07:36

score 3 · Accepted Answer · answered Oct 09 '16 at 07:35

3

You can unpack the Seq using :_*:

val result = withQueryString(toParams: _*)

answered Oct 09 '16 at 07:35

Yuval Itzchakov

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How to transform List of tuples to multiple tuples?

1 Answers1