Dynamically allocate Matrix using typedef

Question

I already have an idea on how to malloc a matrix if it were an int**. But using a typedef, I think have an idea but I'm not so sure.

typedef int LabeledAdjMatrix[SIZE][SIZE];

Do I do it like this?

APSP = (APSPMatrix*)malloc(sizeof(APSPMatrix));

But when I access it I'm gonna have to use *APSP[0][0] and I have no idea how to use this in memset/memcpy.

Is there a proper way of doing this? Both in dynamically allocating and in accessing.

Oh shoot yes. There was a `#define APSPMatrix LabeledAdjMatrix`. I forgot to include that woops. — Bored Chinese, Oct 10 '16 at 06:02
@BoredChinese: I wrote a specific [answer](http://stackoverflow.com/a/39952606/3545273) for your question in the duplicate... Hope it helps — Serge Ballesta, Oct 10 '16 at 06:50
@SergeBallesta thank you for the answer! I can't reply directly to that post of yours since my reputation is below 50 haha. — Bored Chinese, Oct 10 '16 at 08:14

score 1 · Answer 1 · answered Oct 10 '16 at 05:55

My advice would be to not use array typedefs, they make the code harder to read as it is less apparent when array-pointer decay is or isn't happening.

If you want to allocate a contiguous array you can write:

int (*APSP)[SIZE] = malloc( sizeof(int[SIZE][SIZE]) );

and then access it as APSP[0][0].

Your post talks about "malloc as if it were int **", by which I assume you mean you want separate allocations for each rows... but then you would write int **APSP and write a loop to allocate each row, it is really nothing to do with [SIZE][SIZE].

Unfortunately, it's my professor who made the typedef and not me and I'm supposed to use it. :-( — Bored Chinese, Oct 10 '16 at 06:00

Dynamically allocate Matrix using typedef

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