Regex string not ending a character

Asked Oct 10 '16 at 07:19

Active Oct 10 '16 at 07:19

Viewed 109 times

I want to find double values in a string. String like this :

("A1K 90" AK2 90.0000 90.0000d nil nil (QUOTE ("90" "duz" nil nil 4.0)))

I only want 90.0000 and 4.0. Not 90.0000d.

My regex is -?[0-9]+\.[0-9]{1,6}+(?![a-zA-Z])

This works in notepad++. But in c# it errors nested quantifier +.

This problem {}+. Then I removed +. But now my pattern broken.

How can I solve this problem?

asked Oct 10 '16 at 07:19

Emrah Şentürk

1

Use an atomic group - `(?>-?[0-9]+\.[0-9]{1,6}+)(?![a-zA-Z])` (see [this answer](http://stackoverflow.com/a/210286/3832970)). – Wiktor Stribiżew Oct 10 '16 at 07:21
This works but errors in c# again. MatchCollection _collection = Regex.Matches(line, @"(?>-?[0-9]+\.[0-9]{1,6}+)(?![a-zA-Z])") – Emrah Şentürk Oct 10 '16 at 07:28
1

Sorry, the `+` must be removed, forgot to delete it after copy/pasting `(?>-?[0-9]+\.[0-9]{1,6})(?![a-zA-Z])`. I actually wrote about that in the comment I removed: you need to remove the `+` after the limiting quantifier `{1,6}`. – Wiktor Stribiżew Oct 10 '16 at 07:30
1

See http://ideone.com/SQQvJf – Wiktor Stribiżew Oct 10 '16 at 07:38
Thanks Wiktor. Now it works in c#. – Emrah Şentürk Oct 10 '16 at 07:51

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