for loop with incremenation of 5

Question

Use a counter named count that has an initial value of 1, a final value of 20, and an increment of 5.

for(int count=1; count<20; count=count+5)
cout<<count<<endl;

Is the correct approch?

Is this the correct appraoch?? Depends on what you want to do, if you want to get 1,6,11,16 printed on the screen, this is a way to do it. — 463035818_is_not_an_ai, Oct 11 '16 at 08:49
but the output is printing as 1,6,11,16.... 16 is final value.. — RJV, Oct 11 '16 at 08:49
If the first sentence is a task given to you, then you can tell the teacher that it is immpossible to repeatedly add 5 to 1 and end up with a value of 20.... — 463035818_is_not_an_ai, Oct 11 '16 at 08:51
To clarify - while the final value passed to cout is 16, the value of count when the loop ends is 21. — UKMonkey, Oct 11 '16 at 08:52
@UKmonkey But because the variable is a for-loop local it doesn't matter. — Hatted Rooster, Oct 11 '16 at 08:53
It's impossible to say whether the code is correct without knowing what it's supposed to do. The code will run through a set of values. If those are the values that you want, it's correct; if they aren't, it's not. — Pete Becker, Oct 11 '16 at 10:27

score 1 · Answer 1 · edited May 23 '17 at 10:29

1

Yes, or the shorthand version :

for(int count=1; count<=20; count+=5)

Your values will be 1 , 6 , 11 , 16 though. It won't get to 20 so the question is a bit off.

Side note, I see you using cout, this means you either have using namespace std; or using std::cout;, the latter is fine, the former not so much.

edited May 23 '17 at 10:29

Community

1
1

answered Oct 11 '16 at 08:50

Hatted Rooster

35,759
6
62
122

Dam · Answer 2 · 2016-10-12T10:46:27.743

I would use Boost.Range. The interface is quite straighforward and you are explicitly showing your intention which is importan with custom loops.

#include <iostream>
#include <boost/range/irange.hpp>

int main() {
    for (auto i: boost::irange(1, 20, 5)) {
        std::cout << i << std::endl;
    }
    return 0;
}

Stream output operator is already overload so you'll get the value from the type you want.

You can try it live.

score 0 · Accepted Answer · 2016-10-13T10:33:31.800

0

ya correct .. start with initial point 1 and final value of 20 , increment by 5

for(int count=1; count<=20; count=count+5)

edited Oct 13 '16 at 10:33

answered Oct 13 '16 at 09:24

score 0 · Answer 4 · answered Oct 14 '16 at 09:10

0

ya correct .. start with initial point 1 and final value of 20 , increment by 5

for(int count=1; count<=20; count=count+5)

answered Oct 14 '16 at 09:10

RJV

287
1
7
20

score 0 · Answer 5 · answered Oct 20 '16 at 03:26

0

start with initial point 1 and final value of 20 , increment by 5

for(int count=1; count<=20; count=count+5)

answered Oct 20 '16 at 03:26

for loop with incremenation of 5

5 Answers5