C# How do you round number to closest number in a geometric sequence

Question

I am trying to round a number to the closest number in a geometric sequence having a factor of 2 between each number.

Lets say I have:

int num = 30;

I would need "num" to be rounded to 32

any chance you've tried anything other than `int num = 30;` ? could we see some of that? — ethorn10, Oct 11 '16 at 16:16
Related: [Rounding up to nearest power of 2](http://stackoverflow.com/questions/466204/rounding-up-to-nearest-power-of-2) — stuartd, Oct 11 '16 at 16:16
The closest so if "num" was equal to 33, I would need it to be rounded to 32 instead of 64. — Matt J, Oct 11 '16 at 16:17

mybirthname · Accepted Answer · 2016-10-11T16:50:53.097

2

double logValue = Math.Log(30, 2);   
double ceilingValue= Math.Round(logValue);

double result = Math.Pow(2, ceilingValue);

edited Oct 11 '16 at 16:50

answered Oct 11 '16 at 16:16

mybirthname

I tried the code it worked well but only rounded to the next number in sequence instead of going to the closest number. – Matt J Oct 11 '16 at 16:57
@MattJ Yes use Math.Round instead of Math.Ceiling. Like in my edit. – mybirthname Oct 11 '16 at 16:58
It might be worth noting that this method will consider 23 to be closer to 32 than to 16. – Kyle Oct 11 '16 at 17:50

1 Answers1