Replacing php realpth when outputing to users

Question

I used php real path to get actual path of files and directory to delete and after deleted i will print all deleted items. But my problem is that it also show the real path where the file source is and i don't want to show it to users is there any way i can hide the pay and only show the file example.

I don't like it to look like this

[File]: /mnt/wef66/d2/81/557642661/htdocs/useruploads/myfiles/imagefolder/mosaic_1.jpg

[File]: /mnt/wef66/d2/81/557642661/htdocs/useruploads/myfiles/imagefolder/room_home_1.jpg

[Directory]: /mnt/wef66/d2/81/557642661/htdocs/useruploads/myfiles/imagefolder

Is there anyway i can make it look this way using rejex or any method please i need help i have to remove /mnt/wef66/d2/81/557642661/htdocs/

[File]: www.example.com/useruploads/myfiles/imagefolder/mosaic_1.jpg

[File]: www.example.com/useruploads/myfiles/imagefolder/room_home_1.jpg

[Directory]: www.example.com/useruploads/myfiles/imagefolder

Maybe using something like this

echo preg_replace("/mnt/wef66/d2/81/557642661/htdocs", "www.example.com", "[File]: /mnt/wef66/d2/81/557642661/htdocs/useruploads/myfiles/imagefolder/mosaic_1.jpg");

$path = realpath($parentBas);

Possible duplicate of [How do I replace part of a string in PHP?](http://stackoverflow.com/questions/12605060/how-do-i-replace-part-of-a-string-in-php) — Dekel, Oct 12 '16 at 00:01
@Dekel please this is somehow different because i need it loop through all the deleted files and also know here to start please i just need help i have tired to get it done — codesuck, Oct 12 '16 at 00:06
If you have the deleted files in a variable - just loop over this variable and replace the string you want. — Dekel, Oct 12 '16 at 00:08

nanocv · Accepted Answer · 2016-10-12T00:34:42.620

I would use configuration variables $privatePath and $publicPath.

So you can concat whichever you want to the relative paths to your directories or files.

For your example:

$privatePath = '/mnt/wef66/d2/81/557642661/htdocs/';
$publicPath = 'www.example.com/';

$pic1RelativePath = 'useruploads/myfiles/imagefolder/mosaic_1.jpg';

$pic1privatePath = $privatePath . $pic1RelativePath;
// /mnt/wef66/d2/81/557642661/htdocs/useruploads/myfiles/imagefolder/mosaic_1.jpg

$pic1publicPath = $publicPath . $pic1RelativePath;
// www.example.com/useruploads/myfiles/imagefolder/mosaic_1.jpg

I think this is easier and more efficient than replacing the paths with regex.

EDIT:

If you have all the real paths in an array, you can loop through it and replace easily all the private paths with the public paths this way:

$paths = [
'/mnt/wef66/d2/81/557642661/htdocs/useruploads/myfiles/imagefolder/mosaic_1.jpg',
'/mnt/wef66/d2/81/557642661/htdocs/useruploads/myfiles/imagefolder/room_home_1.jpg',
'/mnt/wef66/d2/81/557642661/htdocs/useruploads/myfiles/imagefolder'
];

foreach ($paths as &$path) {
  $path = str_replace($privatePath, $publicPath, $path);
}

print_r($paths);

how this will work? the whole path come in one string and he you just cut it into 2 i can't see anything to use here — codesuck, Oct 12 '16 at 00:15
Ok, maybe I didn't understand well the problem. I've added an example to easily replace the paths if you have them stored in an array. Hope it helps. — nanocv, Oct 12 '16 at 00:36

Replacing php realpth when outputing to users

1 Answers1