How to wait for UI element without failing test case

Question

I have a dialog that displays on first execution of my app. I therefore want my test case to handle responding to the dialog - but only if it appears.

The waitForExpectations method will error out if the timeout is reached.

What is the best way to wait for this element to appear for a short time without failing the test case if it does not appear?

If the dialog only appears when the app is first executed, why not use the testing logic only on the first execution of the app too? — Marcus, Oct 12 '16 at 13:16

score 0 · Accepted Answer · answered Oct 14 '16 at 00:06

You will have to reimplement waiting. As terrible as it sounds, I recommend using Sleep and If statements; you want to lock your test thread while it waits for the app to finish presenting content, then evaluate.

Unfortunately, as far as I'm aware none of the options for waitForExpectationsWithTimeout permit you to not fail the test if the expectationForPredicate is not fulfilled at the end of the timeout time.

score 0 · Answer 2 · edited May 23 '17 at 12:24

0

Try the following code:

addUIInterruptionMonitorWithDescription("SYSTEM_DESCRIPTION") { (alert) -> Bool in
  alert.buttons["BUTTON_TITLE"].tap()
  return true
}

app.buttons["BUTTON_TITLE"].tap()
app.tap()

SYSTEM_DESCRIPTION is the title or description of system alert.

BUTTON_TITLE is like "OK", "Allow", ...

Find out more in this answer: https://stackoverflow.com/a/32228033/6657951

edited May 23 '17 at 12:24

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answered Oct 17 '16 at 18:47

MobileTuts

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How to wait for UI element without failing test case

2 Answers2