Thymeleaf Loop Until a Number

Question

I make a search and get response from server with Thymeleaf. This holds the number of results:

${response.count}

I want to make an iteration like that:

for (int i = 1; i <= response.count; i++) {
    if (response.page == i) {
        <button class="active">Dummy</button>
    } else {
        <button>Dummy</button>
    }
}

How can I do that? I've tried something like that:

${#numbers.sequence(0, response.count)}

but didn't work.

EDIT: I've tried that but didn't work too:

<button th:each="i: ${#numbers.sequence(0, response.count - 1)}" th:class="${i == response.page} ?: active">Dummy</button>

Is this what you're thinking about? http://stackoverflow.com/questions/18490820/spring-thymeleaf-how-to-implement-pagination-for-a-list — riddle_me_this, Oct 12 '16 at 21:00
Try this I don't think you can use "?:" in this case, but "?" works fine. — Metroids, Oct 13 '16 at 15:26
I've accepted your answer but implemented as the way you commented, thanks. — kamaci, Oct 13 '16 at 19:08

score 31 · Accepted Answer · answered Oct 13 '16 at 00:11

31

This works for me:

<th:block th:each="i: ${#numbers.sequence(0, response.count - 1)}">
    <button th:if="${response.page == i}" class="active">Dummy</button>
    <button th:unless="${response.page == i}">Dummy</button>
</th:block>

answered Oct 13 '16 at 00:11

Metroids

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In my case instead of 'response.count' I use 'elements.size()' like this: 'th:each="i: ${#numbers.sequence(0, elements.size()- 1)}"'. Following this condition seems like the case when NO buttons are displayed is impossible. Minimum one button is displayed. – Vladislav Ashikhin Jun 08 '23 at 22:55

Thymeleaf Loop Until a Number

1 Answers1

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