bash if/else compare variable and string parameter

Question

Can someone explain how to correctly do an if/else in bash when comparing a parameter to a string? In detail please, I tried to combine elements of these websites 1 2 3 but I don't know what went wrong.

#!/bin/bash
sellx=125
selly=154 #top
itemwidth=10

#takes in two params $1=buy/sell   $2=number in buy or sell
ModifyItem(){
    if [["$1"=="sell"]] 
    then
        xdotool mousemove "$sellx" "$(($selly+$2*$itemwidth))";
    else
        echo "nope";
    fi
}

ModifyItem sell 2

Have you tried `if [ $1 = "sell" ] then`? – afsafzal Oct 13 '16 at 01:38 — afsafzal, Oct 13 '16 at 01:38

score 1 · Accepted Answer · answered Oct 13 '16 at 01:55

1

Whitespace is important; you need to separate the == operator from its arguments, and you need to separate the brackets from the condition.

if [[ "$1" == "sell" ]]

answered Oct 13 '16 at 01:55

chepner

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bash if/else compare variable and string parameter

1 Answers1