there are several topics about how test method order could be created, but i have some trouble.
I have simply Junit 4.11 TestClass:
public class ServiceTest {
@BeforeClass
public static void setUp() throws IllegalArgumentException, IOException {
try {
service = new Service("myService");
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
@Test
public void testA {
boolean isConnected = false;
try {
isConnected = service.initialService();
assertEquals(true, isConnected);
} catch (Exception e) {
e.printStackTrace();
assertEquals(true, isConnected);
}
}
@Test
public void testB {
try {
//exec some methods....
assertEquals(true, isConnected);
} catch (Exception e) {
e.printStackTrace();
assertEquals(true, isConnected);
}
}
}
The order of testmethod excution must be testA, testB.
Because of that, i´ve created Testsuite:
@RunWith(MySuite.class)
@SuiteClasses({ EwsServiceTest.class })
public class TestSuite {
}
At next i´ve defined Testrunner, which gives me methods testA and testB
public class MySuite extends Suite {
private Method[] children= null;
protected MySuite(Class<?> klass, Class<?>[] suiteClasses) throws InitializationError {
super(klass, suiteClasses);
// TODO Auto-generated constructor stub
}
@Override
protected List<Runner> getChildren() {
//collect testA and testB methods
children = super.getChildren().get(0).getClass().getMethods();
return super.getChildren();
}
@Override
protected void runChild(Runner runner, RunNotifier notifier) {
super.runChild(runner, notifier);
}
}
How and within which introduced class can i set method-order like.
