Go back to a previous git commit

Question

Consider the following git log:

commit 6c7bd597252a1c9b9fe3ddbac1febbfa62b0f06a
Author: ...
Date:   Sat Oct 15 16:22:16 2016 +0200

    mess2

commit 9c9a8198df44d8efa4ee22c2f877e9fc6a16f27b
Author: ..
Date:   Fri Oct 14 15:52:34 2016 +0200

    mess1

commit 43a07c068d5c8d7879a60450a28c05c980ef34de
Author: ..
Date:   Wed Oct 12 11:52:09 2016 +0200

    v0.6.0

It might be too simple: I'd like to discard mess1 and mess2 and carry on just with commit v0.6.0. How can I do this?

I tried the following: git checkout 43a07c0.. but it seems that the files in my directory are not the ones from the desired commit.

Possible duplicate of the second most highly voted question on SO: http://stackoverflow.com/questions/927358/how-to-undo-last-commits-in-git — MD XF, Oct 15 '16 at 14:41
If in fact *"it seems that the files in my directory are not the ones from the desired commit"* then you are likely mistaken about what was committed in the subsequent messes. Use `git show ` or `git diff ^..HEAD` to ensure you're not discarding something you need. — Jeff Puckett, Oct 15 '16 at 15:40

score 0 · Answer 1 · answered Oct 15 '16 at 14:42

0

If you don't mind losing mess1 and mess2, you can

git reset --hard 43a07c068d5c8d7879a60450a28c05c980ef34de

answered Oct 15 '16 at 14:42

Jakub Judas

737
6
16

Go back to a previous git commit

1 Answers1