What is the size of pointers in c++?
char a;
char *b=a;
cout<<sizeof(b);
Output is 2 I don't know why.
cout<<sizeof(const); //o/p is 2
cout<<sizeof(NULL); //o/p is 2
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Himanshu Sharma
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6Are you using turbo c++ for dos? – drescherjm Oct 16 '16 at 03:28
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6If yes, get rid of it and use a modern compiler. – deviantfan Oct 16 '16 at 03:29
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3Btw. `char *b=a;` should be `char *b=&a;` – deviantfan Oct 16 '16 at 03:30
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1Although `char *b=a;` is not valid. – drescherjm Oct 16 '16 at 03:30
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It's *implementation-defined* which means that each compiler can make its own decision. Some compilers may let you configure this behaviour (e.g. in Turbo C++ you can select 2 or 4 by specifying a memory model) – M.M Oct 16 '16 at 03:43
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3Your compiler lets you use `sizeof(const)`? – R Sahu Oct 16 '16 at 03:51
1 Answers
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The size of a pointer in c++ depends on the system you are compiling for and the compiler you are using.
In general, if you are on a 32 bit system the pointer will have a size of 4 bytes. On a 64 bit system it'll be 8 bytes and so on, but that is not guaranteed.
Just use sizeof(char*) and you should get the answer.
jule
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