Regex: I want to match only words without a dot at the end

Question

For example: George R.R. Martin I want to match only George and Martin.

I have tried: \w+\b. But doesn't work!

@WiktorStribiżew My problem is, I dont' know how to negate in regex. How to tell regex that I don't want a dot at the end? The end of the word is `\b`... but what else? — , Oct 16 '16 at 20:55

score 4 · Accepted Answer · edited May 23 '17 at 12:00

The \w+\b. matches 1+ word chars that are followed with a word boundary, and then any char that is a non-word char (as \b restricts the following . subpattern). Note that this way is not negating anything and you miss an important thing: a literal dot in the regex pattern must be escaped.

You may use a negative lookahead (?!\.):

var s = "George R.R. Martin";
console.log(s.match(/\b\w+\b(?!\.)/g));

See the regex demo

Details:

\b - leading word boundary
\w+ - 1+ word chars
\b - trailing word boundary
(?!\.) - there must be no . after the last word char matched.

See more about how negative lookahead works here.

That's all I need. Thank you, so much! I will mark that answer as the best in few mins. — , Oct 16 '16 at 20:59

Regex: I want to match only words without a dot at the end

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