java character position in a string

Question

I was hoping that SO could help me with my issue. I have this code:

public static void main(String[] args) {
    Scanner scanner=new Scanner(System.in);

    System.out.print("Enter a string:\t");
    String word = scanner.nextLine();

    System.out.print("Enter a character:\t");
    String character = scanner.nextLine();

    char charVar = 0;
    if (character.length() > 1) {
        System.err.println("Please input only one character.");
    } else {
        charVar = character.charAt(0);
    }

    int count = 0;
    for (char x : word.toCharArray()) {
        if (x == charVar) {
            count++;
        }
    }

    System.out.println("Character " + charVar + " appears " + count + 
                       (count == 1 ? " time" : " times"));
}

So this code asks the user to enter a string, then it asks the user to enter a character, the program will then tell the user how many times that specific character appears. My problem is that I need to convert this code so it will still ask the user for the string, but wont ask for a character. It will instead ask for the user to enter a number. The program will then show what character is at that position in the string. Example: lets say they enter "string" and then 2 for the number, the program will display the character "r". So my question is basically if any one can give me an idea as how to accomplish this. Any help would be great.

Well, you could start by not ignoring the [documentation](http://docs.oracle.com/javase/8/docs/api/java/lang/String.html) anymore — Tom, Oct 17 '16 at 22:34
When posting [code](http://stackoverflow.com/a/39863009/1248974) taken from other questions, please reference where you got the code from, or better, include only *your* code. — chickity china chinese chicken, Oct 17 '16 at 22:35
Use scanner.nextInt() to take integers and then use String.charAt(int) to get the character at that index from the specified String. — Brunaldo, Oct 17 '16 at 22:37
@Brunaido can you further explain your comment to me, when I do that it says "cannot make static reference to non-static method". — John Smth, Oct 17 '16 at 23:00
@JohnSmth because it matches http://stackoverflow.com/a/39863009/1248974 code exactly, just sayin, no biggie — chickity china chinese chicken, Oct 17 '16 at 23:03
@downshift will ricard was one I made when i forgot my password for this one, thats my second account i forgot about that. — John Smth, Oct 17 '16 at 23:05
@JohnSmth, cool no worries, I'll delete the comment if you prefer, I was just pointing out what I've seen some users complain about. It's all good, I don't mind, and thanks for the accept! — chickity china chinese chicken, Oct 17 '16 at 23:09

score 1 · Accepted Answer · answered Oct 17 '16 at 23:01

1

public static void main(String[] args) {
        Scanner scanner=new Scanner(System.in);

        System.out.print("Enter a string:\t");
        String word = scanner.nextLine();

        System.out.print("Enter an integer:\t");
        int index = scanner.nextInt();

        System.out.println("Character at position " + index + ": " + word.charAt(index));
    }

answered Oct 17 '16 at 23:01

chickity china chinese chicken

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Thank you for the answer. completely unrelated question, how big of an issue is it if you never close your Scanner in a program? – John Smth Oct 17 '16 at 23:11
In a short, simple example like the one here, which is only reading user input, it's not an issue, unless we were to read more input. If we were opening and reading files or other resources, of course, that's when it may become an issue (corrupting files, etc). However, there is no need to close it after using, the Java environment closes it automatically on program termination. – chickity china chinese chicken Oct 17 '16 at 23:22

java character position in a string

1 Answers1