Android SimpleDateFormat Unparsable Date

Question

i got this Date String for example:

Wed, 19 Oct 2016 12:00 PM CEST

now i am trying to convert it to a Calendar with the help of the SimpleDateFormat

SimpleDateFormat sdf = new SimpleDateFormat("EEE, d MMM yyyy hh:m a zzz", Locale.US);

And when i try to parse it i get the following error:

Unparseable date: "Wed, 19 Oct 2016 12:00 PM CEST" (at offset 26)

I appreciate every help!

Edit:

Full parsing code:

@Override
public WeatherData parseCurrentWeatherData(String jsonString) {

    WeatherData weatherData = new WeatherData();

    try {
        JSONObject obj = new JSONObject(jsonString);

        JSONObject mainObj = obj.getJSONObject("query").getJSONObject("results").getJSONObject("channel");

        JSONObject condition = mainObj.getJSONObject("item").getJSONObject("condition");

        Calendar cal = new GregorianCalendar();
        SimpleDateFormat sdf = new SimpleDateFormat("EEE, dd MMM yyyy hh:m a z", Locale.US);
        cal.setTime(sdf.parse(condition.getString("date")));

        weatherData.setCalendar(cal);

    } catch(JSONException | ParseException ex) {
        Log.e("DataFetcher", ex.getLocalizedMessage());
    }

    return weatherData;
}

Solution:

It looks like Android can't parse some timezones. Thanks to @Burhanuddin Rashid for this approach.

String strDate = condition.getString("date").replace("CEST", "GMT+0200");

Solution here: Unparseable date: "Fri Oct 10 23:11:07 IST 2014" (at offset 20)

Just try printing condition.getString("date") to check whether you are getting the right string — Muzy, Oct 19 '16 at 11:06
i checked this already, and yes i got the right string @Muzy — lhuber, Oct 19 '16 at 11:06
when im logging the string im getting this line: "D/YahooWeatherDataParser: Wed, 19 Oct 2016 12:00 PM CEST" - so it's allright — lhuber, Oct 19 '16 at 11:09

Burhanuddin Rashid · Accepted Answer · 2016-10-19T11:47:26.560

2

Please add extra d in it like this :

    SimpleDateFormat sdf = new SimpleDateFormat("EEE, dd MMM yyyy hh:m a zzz", Locale.US);
    sdf.setLenient(true);

edited Oct 19 '16 at 11:47

answered Oct 19 '16 at 10:54

Burhanuddin Rashid

5,260
6
34
51

Try setting this `sdf.setLenient(true);` – Burhanuddin Rashid Oct 19 '16 at 11:46
Try removing comma(,) from "EEE, dd MMM yyyy hh:m a zzz" and from `condition.getString("date")` from this replacce comma(,) with nothing like this `condition.getString("date").replace(",","")` – Burhanuddin Rashid Oct 19 '16 at 11:52
Still got the error "Unparseable date: "Wed 19 Oct 2016 01:00 PM CEST" (at offset 25)" – lhuber Oct 19 '16 at 11:57
i think maybe it has to do with the "CEST" because it always throws the error at the offset position from CEST? – lhuber Oct 19 '16 at 11:58
Its seems IST issue you can refer this it might help :http://stackoverflow.com/questions/27375489/unparseable-date-fri-oct-10-231107-ist-2014-at-offset-20 – Burhanuddin Rashid Oct 19 '16 at 12:01

score 2 · Answer 2 · edited Oct 19 '16 at 11:47

 public static void main(String[] args) throws ParseException {
    String dateString = "Wed, 19 Oct 2016 12:00 PM CEST";
    SimpleDateFormat sdf = new SimpleDateFormat("EEE, d MMM yyyy hh:m a zzz", Locale.US);
    Date date = sdf.parse(dateString);
    Calendar calendar = Calendar.getInstance();
    calendar.setTime(date);
    System.out.println(calendar);
  }

The same thing worked for me.

Make sure all the imports are correct

import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Calendar;
import java.util.Date;
import java.util.Locale;

score 0 · Answer 3 · answered Oct 19 '16 at 11:11

0

Your condition.getString("date") and the format in the "SimpleDateFormat sdf = new SimpleDateFormat("EEE, dd MMM yyyy hh:m a z", Locale.US);" doesn't match.

answered Oct 19 '16 at 11:11

Çağatay Karslı

21
6

there it is @Çağatay Karslı – lhuber Oct 19 '16 at 11:41

Android SimpleDateFormat Unparsable Date

3 Answers3