6

Is there a way to convert a string to binary in Swift?

Found this link on SO but it only handles converting decimals. I'm trying to convert special characters and letters as well.

Tried building an array of known ASCII characters and comparing them(worked for letters) but ran into problems comparing the special characters.

Appreciating your responses.

Community
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AMAN77
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  • I want to break a string down into 1's and zero's no matter what the string contains. Then from there I will move onto phase 2... – AMAN77 Oct 20 '16 at 12:59

3 Answers3

10

Use func data(using encoding: String.Encoding, allowLossyConversion: Bool = default) -> Data?

Example:

Swift 5

let string = "The string"
let binaryData = Data(string.utf8)

Swift 3

let string = "The string"
let binaryData: Data? = string.data(using: .utf8, allowLossyConversion: false)

EDIT: Or wait, do you need binary representation of you data or string of 0/1?

EDIT: For string of 0/1 use something like:

let stringOf01 = binaryData?.reduce("") { (acc, byte) -> String in
    acc + String(byte, radix: 2)
}

EDIT: Swift 2

let binaryData = str.dataUsingEncoding(NSUTF8StringEncoding, allowLossyConversion: false)
AlphaWulf
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user28434'mstep
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2

Swift 5:

This will add a String Extension

extension String {
    func stringToBinary() -> String {
        let st = self
        var result = ""
        for char in st.utf8 {
            var tranformed = String(char, radix: 2)
            while tranformed.count < 8 {
                tranformed = "0" + tranformed
            }
            let binary = "\(tranformed) "
            result.append(binary)
        }
        return result
    }
}

This is going to return a string of 0s and 1s separated by spaces. You can modify it to return an array if needed.

Implementation:

let string = "Hello World"
let newString = string.stringToBinary()
1

For Swift 5, you can add a String Extension like that:

extension String {
    var hexaToBinary: String {
        return hexaToBytes.map {
            let binary = String($0, radix: 2)
            return repeatElement("0", count: 8-binary.count) + binary
        }.joined()
    }

    private var hexaToBytes: [UInt8] {
        var start = startIndex
        return stride(from: 0, to: count, by: 2).compactMap { _ in
            let end = index(after: start)
            defer { start = index(after: end) }
            return UInt8(self[start...end], radix: 16)
        }
    }
}
Medhi
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