Python, For loops depending on int

Question

I have some code which prints every possible letter combination for a word length of 3.

letters = ["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t"    ,"u","v","w","x","y","z"]
for x in range(0,26):
    for y in range(0,26):
        for z in range(0,26):
            print(letters[x],letters[y],letters[z])

This code works fine but if I wanted to see every 4 letter word, then I would have to add another for loop and the same for 5 letters and so on.

I am wondering how I can have a certain number of for loops depending on user input.

The [`itertools`](https://docs.python.org/3/library/itertools.html) module is the right place to look — styvane, Oct 21 '16 at 09:07
You want to generate all possible 4-letter strings, correct? — agg3l, Oct 21 '16 at 09:09
Possible duplicate of [Dimensionality agnostic (generic) cartesian product](http://stackoverflow.com/questions/24648045/dimensionality-agnostic-generic-cartesian-product) — deceze, Oct 21 '16 at 09:10
@agg3l OP wants to generate all possible *n* letter strings, with *n* being a user input. — deceze, Oct 21 '16 at 09:12
If all letters are one character long, you can use a string instead of a list of strings. `["a", "b", "c"][x]` <=> `""abc"[x]` And you should also look at the `string` module, `string.lowercase`. — Oskar Skog, Oct 21 '16 at 09:18

score 5 · Accepted Answer · answered Oct 21 '16 at 09:13

5

You itertools.product with a *repeat=n* where n is how many loops:

from itertools import  product
for p in product(letters,repeat=3):
    print(p)

answered Oct 21 '16 at 09:13

Padraic Cunningham

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Python, For loops depending on int

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