How to substitute a query parameter in a string url

Question

Hello I have a url string like

http://example.com/foo/?bar=15&oof=myp

Now lets say that I want to change the int value in the bar parameter to 16, in order to have

http://example.com/foo/?bar=16&oof=myp

How can I do this? Considering that the number after the = might be of 1, 2 or ever 3 characters. Thank you

have look into this : http://stackoverflow.com/questions/13592236/parse-a-uri-string-into-name-value-collection — Rockstar, Oct 21 '16 at 13:15

amicoderozer · Accepted Answer · 2017-07-31T07:15:03.347

15

You can use UriComponentsBuilder (it's part of Spring Web jar) like this:

String url = "http://example.com/foo/?bar=15&oof=myp";

UriComponentsBuilder urlBuilder = UriComponentsBuilder.fromUriString(url);

urlBuilder.replaceQueryParam("bar", 107);

String result = urlBuilder.build().toUriString();

Substitute 107 with the number you want. With this method you can have URI or String object from urlBuilder.

edited Jul 31 '17 at 07:15

answered Oct 21 '16 at 13:26

amicoderozer

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Exactly what I was looking for. Thanks much. – user11230 Oct 21 '16 at 13:28
Please mention where UriComponentBuilder is sourced from (believe this is from Spring) – Mahesh Jul 22 '17 at 14:10
@Mahesh updated the answer, and yes it's part of spring web jar. – amicoderozer Jul 31 '17 at 07:15

score -3 · Answer 2 · edited Jul 06 '18 at 15:18

-3

Use regex to find the number parameter in the string url
Use String.replace() to replace the old parameter with the new parameter

edited Jul 06 '18 at 15:18

Roshana Pitigala

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answered Oct 21 '16 at 13:17

Max

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I don't know how to use regex – user11230 Oct 21 '16 at 13:24
Mention a working example code as to solve the above issue. – Roshana Pitigala May 31 '18 at 13:59

How to substitute a query parameter in a string url

2 Answers2