Convert string with more than 20 digits to a number using Java

Question

I have this string:

0.023526112354180534

How can I transform this string to number, and maybe more digits? I tried Double.parseDouble and not work

EDIT

You are right.

I´m making a call from Javascript and my call is:

url : "/myapp/data/selectedCampaign/thermal/"+data

data=0.023526112354180534

When I entered this method in Spring

@RequestMapping(value = "/selectedCampaign/{type}/{evidenceValue}", method = RequestMethod.GET)
    public @ResponseBody List<Double> getValues(@PathVariable("type") String type,
            @PathVariable("evidenceValue") String evidenceValue)

evidenceValue is 0 and I was parsing 0

I still don t know why. EDIT 2

I reolve this issue by going to:

Spring MVC @PathVariable with dot (.) is getting truncated

`Double.parseDouble` seems to work perfectly. What issue exactly are you experiencing with it? — Mureinik, Oct 21 '16 at 20:04

score 2 · Accepted Answer · answered Oct 21 '16 at 20:04

2

use new BigDecimal("0.023526112354180534");

answered Oct 21 '16 at 20:04

Timothy Truckle

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Mein Name · Answer 2 · 2016-10-21T20:08:14.100

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double d = Double.parseDouble("0.023526112354180534");
System.out.println(d);

worked without problems for me at least without precision loss

Edit: As far as I know the only difference between Double.parseDouble(String) and BigDecimal is the precision, so if precision is important, you should use BigDecimal

edited Oct 21 '16 at 20:08

answered Oct 21 '16 at 20:04

Mein Name

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Won't work without precision loss for almost any number with more than 16 digits. – FredK Oct 21 '16 at 20:06
@FredK you are right ^^ I was just editing the comment – Mein Name Oct 21 '16 at 20:09

Convert string with more than 20 digits to a number using Java

2 Answers2