When ever I press the send button the TCP Client, it stops the TCP Server and throws me this error.
The calling thread cannot access this object because a different thread owns it.
I've tried debugging it but couldnt find the issue. How would I be able to fix this since it is bugging me alot and I am new to TCP / IP and threading aswell. I know how it works but yeah.
In the listenerThread() method its this line that is throwing me this error.
lbConnections.Items.Add(handlerSocket.RemoteEndPoint.ToString() + " connected.");
using System;
using System.Collections;
using System.IO;
using System.Net;
using System.Net.Sockets;
using System.Threading;
using System.Windows;
using System.Windows.Forms;
using System.Text;
namespace SimpleTCPServer
{
/// <summary>
/// Interaction logic for MainWindow.xaml
/// </summary>
public partial class MainWindow : Window
{
private ArrayList nSockets;
public MainWindow()
{
InitializeComponent();
}
private void Window_Loaded(object sender, RoutedEventArgs e)
{
IPHostEntry IPHost = Dns.GetHostByName(Dns.GetHostName());
lblStatus.Content = "My IP address is " + IPHost.AddressList[0].ToString();
nSockets = new ArrayList();
Thread thdListener = new Thread(new ThreadStart(listenerThread));
thdListener.Start();
}
public void listenerThread()
{
TcpListener tcpListener = new TcpListener(8080);
tcpListener.Start();
while (true)
{
Socket handlerSocket = tcpListener.AcceptSocket();
if (handlerSocket.Connected)
{
Control.CheckForIllegalCrossThreadCalls = false;
lbConnections.Items.Add(handlerSocket.RemoteEndPoint.ToString() + " connected.");
lock (this)
{
nSockets.Add(handlerSocket);
}
ThreadStart thdstHandler = new
ThreadStart(handlerThread);
Thread thdHandler = new Thread(thdstHandler);
thdHandler.Start();
}
}
}
public void handlerThread()
{
Socket handlerSocket = (Socket)nSockets[nSockets.Count - 1];
NetworkStream networkStream = new NetworkStream(handlerSocket);
int thisRead = 0;
int blockSize = 1024;
Byte[] dataByte = new Byte[blockSize];
lock (this)
{
// Only one process can access
// the same file at any given time
Stream fileStream = File.OpenWrite("c:\\my documents\\SubmittedFile.txt");
while (true)
{
thisRead = networkStream.Read(dataByte, 0, blockSize);
fileStream.Write(dataByte, 0, thisRead);
if (thisRead == 0) break;
}
fileStream.Close();
}
lbConnections.Items.Add("File Written");
handlerSocket = null;
}
}
}
TCP Client
using Microsoft.Win32;
using System.IO;
using System.Net.Sockets;
using System.Windows;
using System.Threading;
using System.Net;
using System.Text;
namespace SimpleTCPClient
{
/// <summary>
/// Interaction logic for MainWindow.xaml
/// </summary>
public partial class MainWindow : Window
{
public MainWindow()
{
InitializeComponent();
}
private void browseButton_Click(object sender, RoutedEventArgs e)
{
OpenFileDialog openFileDialog = new OpenFileDialog();
if (openFileDialog.ShowDialog() == true)
fileTextbox.Text = (openFileDialog.FileName);
}
private void btnSend_Click(object sender, RoutedEventArgs e)
{
Stream fileStream = File.OpenRead(fileTextbox.Text);
// Alocate memory space for the file
byte[] fileBuffer = new byte[fileStream.Length];
fileStream.Read(fileBuffer, 0, (int)fileStream.Length);
// Open a TCP/IP Connection and send the data
TcpClient clientSocket = new TcpClient(ipTextbox.Text, 8080);
NetworkStream networkStream = clientSocket.GetStream();
networkStream.Write(fileBuffer, 0, fileBuffer.GetLength(0));
networkStream.Close();
}
}
}