How would I use Try and except in this code?

Question

I don't understand.

I thought TypeError was what I needed. I looked at some examples online and I thought this was right:

def main():
    x = int(input("Input a number:"))
    y = int(input("Input another number:"))
    result = x * y 
    while not result: 
        try:
            result = x * y
        except TypeError: 
            print('Invalid Number')
main()

What *are* you getting? I'm going to guess a `ValueError` for integer conversion — Andrew Li, Oct 23 '16 at 04:21
@Laptic If you input `0` as one number then your code enters into infinite loop — R__raki__, Oct 23 '16 at 10:26

R__raki__ · Accepted Answer · 2016-10-24T06:05:31.770

0

Include input's in try and except statements

def main():
    while True:
        try:
            x = int(input("Input a number:"))
            y = int(input("Input another number:"))
            break
        except ValueError:
            print('invalid Number')
    result=x*y
    print(result)

edited Oct 24 '16 at 06:05

answered Oct 23 '16 at 10:37

R__raki__

847
4
15
30

1

Thank you! So Whenever I'm using try and except... I have to always put the variables in the try method? – Laptic Oct 23 '16 at 15:23
You have to put the lines that may cause an exception in the `try` block. In your code, the exception will be raised by the `int` function. So only the two input lines need to be inside the try block. You would then need to loop around the try: except blocks, and escape from the loop after a valid input is received. See http://stackoverflow.com/questions/23294658/asking-the-user-for-input-until-they-give-a-valid-response?rq=1 – James K Oct 23 '16 at 20:57

How would I use Try and except in this code?

1 Answers1