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I am currently creating a shooting game that involves a laser rifle, the idea behind the laser rifle is that its a shot that passes through multiple monsters. which is why I don't remove it from the list yet I want to be able to flag a monster that has been hit so there won't be the issue that while the single shot is passing through the monster sprite it won't cause hit multiple times.
What I am trying to do so far is to distinguish between when its hitting a monster and not and according to that damage or not damage but I am having an issue where because the monster is moving its acting as if they are touching - not touching and touching again causing the damage to repeat itself.
This is what my code looks like:

for bullet in bullet_list:
    monster_hit_list = pygame.sprite.spritecollide(bullet,monster_list,False)
    if len(monster_hit_list) == 0:
        being_hit = False
    else:
        for monster in monster_hit_list:
            if flag == False:
                flag = True
                if bullet.rel_path != "Sprite Images/Beam.png":  # If not lazer
                    animation_bullet.add(bullet)
                if being_hit == False:
                    monster.current_hp -= My_Man.current_weapon.damage
                    print monster.current_hp
                    being_hit = True
                if monster.current_hp <= 0:
                    monster_list.remove(monster)
                    character_list.remove(monster)
            if bullet.rel_path != "Sprite Images/Beam.png": #If not lazer
                bullet_list.remove(bullet)
            flag = False
Noob_Programmer
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  • I'm not entirely sure I understood your problem completely. If the monster is hit, moves away from the laser, and moves back into it shouldn't he suffer the damage twice ? – Sorade Oct 27 '16 at 15:28
  • @Sorade The problem is that a single laser deals damage multiple times to the same monster. What I wanted it to do was basically pass through enemies and damage them once per laser – Noob_Programmer Oct 30 '16 at 12:13

0 Answers0