Replace a XML pattern using SED

Question

I have below XML

<defns:Code typeCode="Name">
John
</defns:Code>
<defns:Code1 typeCode="ID">
12345
</defns:Code1>
<defns:Code2 typeCode="address">
Addresss 1234
</defns:Code2>
<defns:Text typeCode="Name">
Doe
</defns:Text>
<defns:Text2 typeCode="ID">
 123
</defns:Text2>
<defns:Text3 typeCode="Address">
Address 4567
</defns:Text3>

and so on element Code[1..n],Text[1..n] in the file has to be replaced with Code

<defns:Code typeCode="Name">
John
</defns:Code>
<defns:Code typeCode="ID">
12345
</defns:Code>
<defns:Code typeCode="address">
Addresss 1234
</defns:Code>
<defns:Text typeCode="Name">
Doe
</defns:Text>
<defns:Text typeCode="ID">
 123
</defns:Text>
<defns:Text typeCode="Address">
Address 4567
</defns:Text>

Can this be done using SED or AWK. Any help is much appreciated!

Don't use regex-based tools to parse or manipulate XML. – kjhughes Oct 25 '16 at 14:11 — kjhughes, Oct 25 '16 at 14:11

score -1 · Answer 1 · answered Oct 25 '16 at 14:11

-1

I'd use sed:

s@\(</*defns:Code\)[0-9]*@\1@

That strips trailing digits by replacing the prefix plus the digits with only the prefix.

answered Oct 25 '16 at 14:11

John Zwinck

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Replace a XML pattern using SED

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