How can I Partition the number in an EditText?

Question

I want to Partition the input number to use its ciphers.
For example, I have an input number : 1563
How can I separate 1, 5, 6 and 3 and use them as separate integers?

package todicemal;

public class um {

    public static void main(String[] args) {
        // TODO Auto-generated method stub
        int k=1563;
        System.out.println(k);
    }

}

How can I use the parts of k which form 1563 and use every single cipher as an integer?

I agree this question isn't well researched as it has been asked before. — Dolf Andringa, Oct 25 '16 at 23:44

azizj · Answer 1 · 2016-10-25T22:36:20.913

0

Stack<Integer> list = new Stack<Integer>();    
while (k > 0) {
  list.push(k % 10);
  k /= 10;
}

edited Oct 25 '16 at 22:36

answered Oct 25 '16 at 22:15

azizj

3,428
2
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That will give you the numbers in reverse order. – BlackHatSamurai Oct 25 '16 at 22:18
Thanks ,but how i can use every nomber ? – Amna97al Oct 25 '16 at 22:29
Thanks @BlackHatSamurai - answer updated – azizj Oct 25 '16 at 22:37

score 0 · Answer 2 · edited May 23 '17 at 12:00

0

As pointed out in the answer here by jjnguy, you can just do:

int number; // = and int
LinkedList<Integer> stack = new LinkedList<Integer>();
while (number > 0) {
    stack.push( number % 10 );
    number = number / 10;
}

while (!stack.isEmpty()) {
    print(stack.pop());
}

edited May 23 '17 at 12:00

Community

1
1

answered Oct 25 '16 at 22:19

BlackHatSamurai

23,275
22
95
156

score 0 · Answer 3 · answered Oct 25 '16 at 23:40

0

You can also do the following

int value = 1563;
char[] charValue = String.valueOf(value).toCharArray();

for (char c: charValue) {
    int num = Character.getNumericValue(c);
    //Use num
}

answered Oct 25 '16 at 23:40

cswace

1
1

How can I Partition the number in an EditText?

3 Answers3