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I'm trying call a method initialised by pointer to a method of other class, i've followed this: but it has not worked for me.

consider this:

class y
{
    public:
        int GetValue(int z)
        {
            return 4 * z;
        }
};


class hooky
{
    public:     
        int(hooky::*HookGetValue)(int);
};


int(hooky::*HookGetValue)(int) = (int(hooky::*)(int))0x0; // memory address or &y::GetValue;



int main()
{
    hooky h; // instance
    cout << h.*HookGetValue(4) << endl; // error
    return 0;
}

the error that produces is:

[Error] must use '.' or '->' to call pointer-to-member function in 'HookGetValue (...)', e.g. '(... ->* HookGetValue) (...)'

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MindLerp
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1 Answers1

1

The correct syntax to invoke a member function pointer is

(h.*HookGetValue)(4)

Update: the reason original code does not work as expected is because of operator precedence of C++: function invocation () is having higher precedence than ptr to member .*. Which means

h.*HookGetValue(4)

will be see as 

h.*(HookGetValue(4))
Adrian Shum
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