Limit a double to two decimal places without trailing zeros

Question

I read this and that. I want this exactly:

1.4324 => "1.43"
9.4000 => "9.4"
43.000 => "43"

9.4 => "9.40" (wrong)
43.000 => "43.00" (wrong)

In both questions the answers points to NSNumberFormatter. So it should be easy to achieve, but not for me.

- (void)viewDidLoad {
    [super viewDidLoad];
    UILabel *myLabel = [[UILabel alloc] initWithFrame:CGRectMake(50, 100, 200, 20)];

    NSNumberFormatter *doubleValueWithMaxTwoDecimalPlaces = [[NSNumberFormatter alloc] init];
    [doubleValueWithMaxTwoDecimalPlaces setNumberStyle:NSNumberFormatterDecimalStyle];
    [doubleValueWithMaxTwoDecimalPlaces setPaddingPosition:NSNumberFormatterPadAfterSuffix];
    [doubleValueWithMaxTwoDecimalPlaces setFormatWidth:2];

    NSNumber *myValue = [NSNumber numberWithDouble:0.01234];
    //NSNumber *myValue = [NSNumber numberWithDouble:0.1];

    myLabel.text = [doubleValueWithMaxTwoDecimalPlaces stringFromNumber:myValue];

    [self.view addSubview:myLabel];
    [myLabel release];
    myLabel = nil;
    [doubleValueWithMaxTwoDecimalPlaces release];
    doubleValueWithMaxTwoDecimalPlaces = nil;
}

I also tried it with

NSString *resultString = [NSString stringWithFormat: @"%.2lf", [myValue doubleValue]];
NSLog(@"%@", resultString);

So how can I format double values with maximum two decimal places? If the last position contains a zero the zero should be left out.

Solution:

NSNumberFormatter *doubleValueWithMaxTwoDecimalPlaces = [[NSNumberFormatter alloc] init];
[doubleValueWithMaxTwoDecimalPlaces setNumberStyle:NSNumberFormatterDecimalStyle];
[doubleValueWithMaxTwoDecimalPlaces setMaximumFractionDigits:2];
NSNumber *myValue = [NSNumber numberWithDouble:0.01234];
NSLog(@"%@",[doubleValueWithMaxTwoDecimalPlaces stringFromNumber:myValue]];
[doubleValueWithMaxTwoDecimalPlaces release];
doubleValueWithMaxTwoDecimalPlaces = nil;

Do you want rounding? That is should 1.4363 => "1.43" or "1.44"? — Nick Moore, Oct 26 '10 at 17:48
Do not forget to release doubleValueWithMaxTwoDecimalPlaces after all... — Lukasz, Dec 15 '10 at 22:23

score 45 · Accepted Answer · answered Oct 26 '10 at 17:51

45

Try adding the following line, when configuring your formatter:

    [doubleValueWithMaxTwoDecimalPlaces setMaximumFractionDigits:2];

answered Oct 26 '10 at 17:51

Chris Gummer

4,772
1
24
17

score 1 · Answer 2 · answered Apr 10 '17 at 10:34

1

 NSNumberFormatter *numberFormatter = [[NSNumberFormatter alloc] init];
[numberFormatter setNumberStyle:NSNumberFormatterDecimalStyle];
[numberFormatter setRoundingMode:NSNumberFormatterRoundDown];
[numberFormatter setMinimumFractionDigits:2];
numberFormatter.positiveFormat = @"0.##";
NSNumber *num = @(total_Value);

answered Apr 10 '17 at 10:34

Nirav Ghori

69
5

pl explain your answer – Sahil Mittal Apr 10 '17 at 10:55
@SahilMittal Above code NSNumberFormatterRoundDown return value without round, then positiveFormat only give two fraction point value. – Nirav Ghori Apr 11 '17 at 07:12

score 0 · Answer 3 · answered Oct 26 '10 at 18:05

How about trimming the unwanted characters from the end of the string?:

NSString* CWDoubleToStringWithMax2Decimals(double d) {
    NSString* s = [NSString stringWithFormat:@"%.2f", d];
    NSCharacterSet* cs = [NSCharacterSet characterSetWithCharacterInString:@"0."];
    NSRange r = [s rangeOfCharacterInSet:cs
                                 options:NSBackwardsSearch | NSAnchoredSearch];
    if (r.location != NSNotFound) {
      s = [s substringToIndex:r.location];
    }
    return s;
}

Even though this solution works there's a much better solution (see accepted answer) — Muxa, Feb 10 '15 at 01:02

Limit a double to two decimal places without trailing zeros

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