check if value is above 0 not working

Question

$number1 = $_POST['zombie'];
if ($number1 > 0){
echo "greater than 0";
}

Now my script just says when the $_POST is -1 that it still is greater than 0. Is there some code that checks for values under 0?

Try #2:

$number1 = $_POST['number'];
if ($number1 > 0 && !($number1 < 0){
echo "greater than 0";
}

Still doesn't work...

echo gettype($number1) returns: NULL

So i did the "print_r($_POST)"

and it returns:

Array
(
    [zombie] => -1
    [droid] => 0
    [alien] => 0
    [rpc] => 0
)

my form:

<form method="post" action="index.php">
    <input type="number" class="form-control" value="0" name="zombie"> <br />
    <input type="number" class="form-control" value="0" name="droid"> <br />
    <input type="number" class="form-control" value="0" name="alien"> <br />
    <input type="number" class="form-control" value="0" name="rpc"> <br />
</form

assign statically value to `$_POST['number']` its working and the problem behind post — Karthi, Oct 26 '16 at 12:27
you sure your form isn't failing you, the one you didn't post? — Funk Forty Niner, Oct 26 '16 at 12:27
uhm when i test it with: echo gettype($number1) the output is: NULL — emiel popelier, Oct 26 '16 at 12:29
post your full code and leave the guesswork out of things. Or, see the answer given below. I for one was never really good at doing guesswork, unless it was something I am used to knowing of an unknown. — Funk Forty Niner, Oct 26 '16 at 12:30
All PHP developers need to know this: `echo "
",print_r($_REQUEST),"
";` - If it's an array, LOOK INSIDE IT! Don't just assume. :-) — Jack Hales, Oct 26 '16 at 12:31
Check my answer below, and check what is in this `$_POST['number']` — Karol Gasienica, Oct 26 '16 at 12:33
`$_POST['number']` there, you have NO input bearing the `number` name attribute which is why your code failed and have wasted everyone's time, including your own. — Funk Forty Niner, Oct 26 '16 at 12:47
Possible duplicate of [PHP: “Notice: Undefined variable” and “Notice: Undefined index”](http://stackoverflow.com/questions/4261133/php-notice-undefined-variable-and-notice-undefined-index) — Funk Forty Niner, Oct 26 '16 at 12:47
why are you doing this Stealth editing????????? now I'm really out of this question. — Funk Forty Niner, Oct 26 '16 at 12:48

Karol Gasienica · Accepted Answer · 2016-10-26T12:49:25.890

0

Maybe you just wrong posting your data? Check what is in $_POST['number'].

echo $_POST['number'];

You can always check your whole $_POST array, maybe you just made a mistake in your variable name? If you want to do it:

echo "<pre>";
print_r($_POST);
echo "</pre>";

There is no input in your code with name="number" You need something like that:

<input type="number" class="form-control" value="0" name="number"> <br />

edited Oct 26 '16 at 12:49

answered Oct 26 '16 at 12:28

Karol Gasienica

2,825
24
36

why someone gives minus if answer shows better code? – marcus Oct 26 '16 at 12:30
1

Not the down voter but @marcus - Maybe because the code isn't actually better and a ternary operator isn't always the answer, the question is "How to check if value is greater than" not "How to check if value is set" – Epodax Oct 26 '16 at 12:35
But there is still an question about what's in that `$_POST['number']`. I think you should focus on whole answer, not only at first line. – Karol Gasienica Oct 26 '16 at 12:37
i did the print_r see above – emiel popelier Oct 26 '16 at 12:40
2

You don't use answers to debug / request information from the asker, that's what ***comments*** are for. – Epodax Oct 26 '16 at 12:40
@emielpopelier can you post what you got? – Karol Gasienica Oct 26 '16 at 12:41
1

As you can see, there is no `'number'` in this array, please post us your `
`.
– Karol Gasienica Oct 26 '16 at 12:42
1

Do you get a badge for changing the most edits in a period of time? – Kitson88 Oct 26 '16 at 12:45
1

@KarolGasienica *"please post us your
"* - I did that [*when?....*](http://stackoverflow.com/questions/40262264/check-if-value-is-above-0-not-working#comment67784947_40262264) *lol!!* too funny. Not my downvote here btw.
– Funk Forty Niner Oct 26 '16 at 12:45
@Kitson88 i bet there is no such thing, just trying to make a helpful answer. Let's focus on problem. – Karol Gasienica Oct 26 '16 at 12:47
posted my form in my question above – emiel popelier Oct 26 '16 at 12:47
If you want to use a `$_POST['number']` you need to make your input with `name="number"` – Karol Gasienica Oct 26 '16 at 12:48
yes i have that in my code but when i rewrote it here i made a mistake – emiel popelier Oct 26 '16 at 12:49
Good :) We found a solution ;) If it helps, just accept my answer :) Thanks! – Karol Gasienica Oct 26 '16 at 12:50

score 0 · Answer 2 · edited Oct 27 '16 at 09:57

0

<?php
if(isset($_POST['button']))
{
$number = $_POST['zombie'];
    if($number > 0)
    {
        echo "number is greater";
    }
    else
    {
        echo "number is less";
    }
}

?>
<form method="post" action="">
  <input type="number" class="form-control" value="0" name="zombie"> <br />
  <input type="number" class="form-control" value="0" name="droid"> <br />
  <input type="number" class="form-control" value="0" name="alien"> <br />
  <input type="number" class="form-control" value="0" name="rpc"> <br />
  <input type="submit" name="button" value="submit">
</form>

edited Oct 27 '16 at 09:57

Karol Gasienica

2,825
24
36

answered Oct 26 '16 at 13:21

detective

43
5

Just need to add a button in the end of the form – detective Oct 26 '16 at 13:22

check if value is above 0 not working

2 Answers2