how to find '\' in a string in Python 3

Question

I am trying to write a function strip white-spaces from the left hand side a string.

def main():
    str_strip = input('enter a string of which whitespace are stripped: ')
    cs-strip(str_strip)

def cs-strip(str_strip):
    i = 0
    temp = list(str_strip)
    if  temp[0] == ' ':
        temp.remove(temp[0])
    elif temp[0] == '\' :
        if temp[1] == 'n' or temp[1] == 't':
            temp.remove(temp[0])
            temp.remove(temp[0])
    new = ''.join(map(str,temp))
    print(new)

main()

But I cant quote compare '\' with other strings, I have tried '''\''', it still doesn't work. How can I compare string when string is or includes '\'?

you need to escape `\ ` character with `\ `, withich would be `temp[0] == '\\'` — Tomasz Plaskota, Oct 28 '16 at 07:49
The syntax says "missing a closing quote[']",which is not helpful — Byron, Oct 28 '16 at 07:51
there's a much shorter way to remove whitespace or backslash from the left side — RomanPerekhrest, Oct 28 '16 at 07:52
thanks! Our homework was to rewrite all the built-in functions. — Byron, Oct 28 '16 at 07:53

score 0 · Accepted Answer · answered Oct 28 '16 at 07:52

0

Use '\\' or r'\' to compare with backslash like below.

temp[0] == '\\'
temp[0] == r'\'

answered Oct 28 '16 at 07:52

Nishu Tayal

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Try this in an interpreter. – TigerhawkT3 Oct 28 '16 at 07:52

score 0 · Answer 2 · answered Oct 28 '16 at 07:53

0

All you need is to escape it with other \ char, so your elif should be like this:

elif temp[0] == '\\' :

answered Oct 28 '16 at 07:53

Or Duan

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how to find '\' in a string in Python 3

2 Answers2