Trying to get compile time method and object selection without base class and virtual calls.
Here is the case:
struct A {
void f1()const { cout << "A::f1" << endl;}
void f2()const { cout << "A::f2" << endl;}
};
struct B {
void f1()const { cout << "B::f1" << endl;}
void f2()const { cout << "B::f2" << endl;}
};
class Holder {
A* _a = nullptr;
B* _b = nullptr;
public:
Holder(A* a): _a(a) {}
Holder(B* b): _b(b) {}
void f1()const {
if(_a) _a->f1();
else if(_b) _b->f1();
}
void f2()const {
if(_a) _a->f2();
else if(_b) _b->f2();
}
};
void f(const Holder& h) {
h.f1();
}
int main() {
B obj;
Holder h(&obj);
f(h);
}
http://coliru.stacked-crooked.com/a/4b5acec6866cfd4e
Suppose there are very few classes like A and B but there may be a lot of functions like f1 and f2.
Holder needs to call function on the actual object that it holds, without polymorphism and without a need for inheritance / shared interface for A and B.
Looking for a nice way to do something like:
class Holder {
A* _a = nullptr;
B* _b = nullptr;
public:
Holder(A* a): _a(a) {}
Holder(B* b): _b(b) {}
// below is pseudo code!
void call<function>()const {
if(_a)
_a->function(); // function is known in compile time, sort of...
else if(_b)
_b->function();
}
void f1()const { call<f1>(); }
void f2()const { call<f2>(); }
};
Any idea?
- macro?
- template?
- other trick?