Suppose I have a list like
list1 = ['A','B','1','2']
When i print it out I want the output as
AB12
And not
A B 1 2
So far I have tried
(a)print list1,
(b)for i in list1:
print i,
(c)for i in list1:
print "%s", %i
But none seem to work. Can anyone suggest an alternate method Thank you.
From your comments on @jftuga answer, I guess that the input you provided is not the one you're testing with. You have mixed contents in your list.
My answer will fix it for you:
lst = ['A','B',1,2]
print("".join([str(x) for x in lst]))
or
print("".join(map(str,lst)))
I'm not just joining the items since not all of them are strings, but I'm converting them to strings first, all in a nice generator comprehension which causes no memory overhead.
Works for lists with only strings in them too of course (there's no overhead to convert to str if already a str, even if I believed otherwise on my first version of that answer: Should I avoid converting to a string if a value is already a string?)
Try this:
a = "".join(list1)
print(a)
This will give you: AB12
Also, since list is a built-in Python class, do not use it as a variable name.
