Why scanf after the if block do not work it just displays "press 1 to enter again:" and do not take input again

Question

scanf statement after if block is not working can somebody help me please

#include<stdio.h>
    main()
    {

        int input,itemno,input2;
        int name1,price1,name2,price2,name3,price3;
        printf("enter input:\n");
        scanf("%d", &input);
        if(input==1)
        {
            printf("enter number of items:\n");
            scanf("%d",&itemno);
            if(itemno<=3)
            {
                printf("enter name and age:\n");
                scanf("%d %d\n %d %d\n %d %d\n",&name1,&price1,&name2,&price2,&name3,&price3);
            }
         else
            printf("you can only enter 3 students");
     }
        printf("press 1 to enter again: \n");
        scanf("%d",&input2);
        if(input2==1)
        {
            printf("hey");
        }
    }

Are you supposed to enter *numbers* for the "name"? Why do you need to enter name and prices three times? Why aren't you telling the user that he or she needs to enter three names and prices? — Some programmer dude, Nov 02 '16 at 06:41
Also please [read about how to ask good questions](http://stackoverflow.com/help/how-to-ask). Just saying "is not working" is not enough. ***How*** is it "not working"? Have you checked what [`scanf`](http://en.cppreference.com/w/c/io/fscanf) returns? Have you used a debugger to step through the code? That information should be in the question body. — Some programmer dude, Nov 02 '16 at 06:43
I don't understand what this code is trying to do. Please clarify what you want to achieve with a sample output. — RoadRunner, Nov 02 '16 at 08:14

score 0 · Answer 1 · answered Nov 02 '16 at 07:16

0

scanf("%d %d\n %d %d\n %d %d\n",&name1,&price1,&name2,&price2,&name3,&price3);

Don't use escape characters in scanf function call.

answered Nov 02 '16 at 07:16

Vijay S B

1,251
1
13
24

Why not? Can you elaborate this? – David Ranieri Nov 02 '16 at 07:20
just ignore what input is being provided. I wanted to ask that if first if statement gets true then why it dont go to scanf after if block – anam Nov 02 '16 at 07:28
There are two if blocks. which one you are saying? – Vijay S B Nov 02 '16 at 07:52
@Keine [link](http://stackoverflow.com/questions/15740024/scanf-asking-twice-for-input-while-i-expect-it-to-ask-only-one) – Vijay S B Nov 02 '16 at 08:28

score 0 · Answer 2 · answered Nov 02 '16 at 08:04

0

just delete the last \n in your scanf the result is : result

answered Nov 02 '16 at 08:04

guoqiang Wei

83
2
6

as for why?<\p> – guoqiang Wei Nov 02 '16 at 08:06
this is because in scanf function ,the \n and space and the tabs ARE seen as blank symbols. – guoqiang Wei Nov 02 '16 at 08:08
so if you have a \n in scanf , when you have entered 6 int, it wait for one another symbol to match the space blank causded by the \n. – guoqiang Wei Nov 02 '16 at 08:11
and in the input buffer when the scanf function finish ,there are also a extra symbol, when it runs to another scanf ,the scanf first scan the input buffer ,so cause the error! – guoqiang Wei Nov 02 '16 at 08:13

Why scanf after the if block do not work it just displays "press 1 to enter again:" and do not take input again

2 Answers2