Get Result View or Dynamic View of an object

Question

I take a json object and deserialize it to a variable. When I debug, I see that each element listed like an array in Results View, but no matter what I tried, I couldn't get these values. My json string:

string json_string = { "baslik" : "bbbbb", "soru1" : "11","soru2" : "22","soru3" : "33"};

var my_object = JsonConvert.DeserializeObject(json_string);

When I debug, I see 'my_object' has Results View and Dynamic View which hold elements I need. How can I get them. I tried everything and searched in web but could not found anything.

score 2 · Answer 1 · answered Nov 02 '16 at 10:37

2

You can use the dynamic variable and JObject.Parse to get values like this:

dynamic my_object = JObject.Parse(json_string);
Console.WriteLine(my_object.baslik);

answered Nov 02 '16 at 10:37

Oluwafemi

14,243
11
43
59

score 0 · Answer 2 · answered Nov 02 '16 at 10:31

Try to do it like this:

        string json_string ="{ 'baslik' : 'bbbbb', 'soru1' : '11','soru2' : '22','soru3' : '33'}";
        var jsonObject = (JObject)JsonConvert.DeserializeObject(json_string);
        Console.WriteLine(jsonObject.GetValue("baslik"));

score 0 · Answer 3 · answered Dec 29 '17 at 20:10

You could also try using JsonConvert.DeserializeObject or DeserializeAnonymousType and pass a type definition as parameter.

This will allow you to test both the structure of your data matches expectation, and you will be able to access expected properties directly off the resulting object rather than having to add a dependency on JObject.

See documentation for examples: https://www.newtonsoft.com/json/help/html/DeserializeAnonymousType.htm

Get Result View or Dynamic View of an object

3 Answers3