Regex match tag

Question

I want to select a tag without custom class in my string have another a tag cannot select that's, String :

<h3 class="r"><a dir="rtl" class="sla" href="#"><span>test<span></a></h3>
<h3>test1</h3>
<h3 class="r"><a class="test" href="#">test2</a></h3>
<h3>test3</h3>

my Reg:

preg_match_all('@<h3\s*class="r">\s*<a[^<>]*href="([^<>]*)"[^<>]*>(.*)</a>\s*</h3>@siU',
        $file, $matches);

how i can select all in pattern a tag without class="sla"

Sidenote: I'm not entirely sure about this, but using the `@` symbol here may not be a good idea. PHP might see that as an error suppressor. Try a different one. — Funk Forty Niner, Nov 02 '16 at 16:05
Possible duplicate of [How do you parse and process HTML/XML in PHP?](http://stackoverflow.com/questions/3577641/how-do-you-parse-and-process-html-xml-in-php) — chris85, Nov 02 '16 at 16:11
Boss @WiktorStribiżew is right, don't use `regex` for this kind of task, use DOM Parser instead. — A l w a y s S u n n y, Nov 02 '16 at 16:12
Thanks all,but this reg pattern worked now for me ,and select all title between tag,But I'm going to just select title As lacking — lock, Nov 02 '16 at 16:24

score 1 · Accepted Answer · answered Nov 02 '16 at 17:32

Use regexp "negative lookahead" <a(?![^<>]*sla)... will discard all results with all "sla" inside "a" tag.

preg_match_all('@<h3\s*class="r">\s*<a(?![^<>]*sla)[^<>]*href="([^<>]*)"[^<>]*>(.*)<\/a>\s*<\/h3>@siU',
$file, $matches)

Also you can use more precise statement: <a(?![^<>]*class=\"sla\")...

Additional information about the "lookaround" expressions: http://www.regular-expressions.info/lookaround.html

Regex match tag

1 Answers1