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Has anybody been able to implement this functionality?

http://php.net/manual/en/session.upload-progress.php

The tl;dr is that when POSTing a form containing a file, if you include an input with the "name" attribute set to the value of session.upload_progress.name in php.ini, then PHP will populate $_SESSION with data about the status of the upload.

Form:

<form action="upload.php" method="POST" enctype="multipart/form-data">
 <input type="hidden" name="<?php echo ini_get("session.upload_progress.name"); ?>" value="123" />
 <input type="file" name="file1" />
 <input type="file" name="file2" />
 <input type="submit" />
</form>

upload.php

(not important but obviously this is where you would normally give the file its actual name and move the uploaded file from the temp to a real directory)

<?php

print_r($_FILES);

?>

session.php:

Run this separate PHP file during the file upload to check for progress

<?php

$key = ini_get("session.upload_progress.prefix") .  $_POST[ini_get("session.upload_progress.name")];
var_dump($_SESSION[$key]);
?>

I have tried every fathomable variation in these scripts and in php.ini settings and no matter what the $_SESSION array is never populated with any upload data. Session_start() is called by default. I tried in both v. 5.4 and 5.6. I have tried everything suggested in the comments in the PHP documentation including running with and without FastCGI. I have in general tried everything.

This is important because I am working on a desktop application that uses POST requests to communicate with .php scripts on a web server, I am not using the browser so JS/HTML5 solutions are not part of the picture. It is also impossible to write your own progress measuring functionality in PHP because the script which handles a file upload (upload.php) doesn't actually run until the upload (to the temp directory with a random name) is complete. There is no way to find out what actual file a temp is associated with until the upload is finished and the upload script runs, allowing access to $_FILES. Please help, I have tried every fathomable possibility. Thanks.

Benjamin Mitchell
  • 26
  • 3

1 Answers1

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Form: //Looks Ok

    <form action="upload.php" method="POST" enctype="multipart/form-data">
    <input type="hidden" name="<?php echo ini_get("session.upload_progress.name"); ?>" value="123" />
 <input type="file" name="file1" />
 <input type="file" name="file2" />
 <input type="submit" />
</form>

Upload.php //Looks Ok too

<?php

print_r($_FILES);

?>

Session.php //recommend some changes here

<?php
session_start();//leave this out if you are session is starting automatically
$key = ini_get("session.upload_progress.prefix") ."123"; //123 value of hidden input
var_dump($_SESSION[$key]);
?>

The major challenge is in your form html view their is no link or call to the session.php. (i dont like the name session.php I have this part of me thats scared it may tamper with $_SESSION scoper). Ideally you can(most folks do) use JS/Ajax call to query Session.php to get result. In which case I'd recommend:

Form:(remember to import jquery before this)

<form action="upload.php" method="POST" enctype="multipart/form-data">
<input type="hidden" name="<?php echo ini_get("session.upload_progress.name"); ?>" value="123" />
<input type="file" name="file1" />
<input type="file" name="file2" />
<input type="submit" />
</form>
<script>
$(document).ready(function(){
  $('form').on('submit',function(){
    $.get( "session.php", function( response ) {
    console.log( response ); // server response-$_SESSION dump
});
  })
})
</script>

session.php:

<?php
session_start();//leave this out if you are session is starting automatically
$key = ini_get("session.upload_progress.prefix") ."123"; //123 value of hidden input
var_dump($_SESSION[$key]);//or echo $_SESSION[$key]["bytes_processed"]. I am not sure how the array would playout inside the returned JSON
?>
Obumneke Princewill Okorie
  • 11
  • 1