NSWidgetExtensionContext openURL Swift

Question

I have been attempting to implement a button to open my iOS app from its widget. I realize this issue has been beaten to death on the forums but I cannot find explanation with the specific error I am receiving. Perhaps some of you more experienced iOS developers can shed some light on this.

I am developing an update to one of my iOS apps for iOS 10 using XCode 8.1 and Swift 2.

Code for my widget's button:

URL scheme added to the widget's info.plist:

The runtime error I receive when pressing the OpenApp button:

AppWidget[11872:3577323] __55-[_NCWidgetExtensionContext openURL:completionHandler:]_block_invoke failed: Error Domain=NSOSStatusErrorDomain Code=-10814 "(null)"

// Note: app name has been substituted with appropriate generics.

Did you find the solution to your problem? I also have registered my url-scheme and my extension is trying to open my app, but I only see `[_NCWidgetExtensionContext openURL:completionHandler:]_block_invoke failed: Error Domain=NSOSStatusErrorDomain Code=-50 "(null)"` in the console. Maybe it's the same issue?!? — Georg, Nov 20 '18 at 10:38

score 11 · Answer 1 · answered Dec 14 '16 at 10:05

11

I often find the OS Status lookup site pretty useful to infer details from errors. An OS error with code -10814 is a kLSApplicationNotFoundErr, which describes the scenario when:

No application in the Launch Services database matches the input criteria.

It sounds like your application has not been properly registered with the system as a consumer of the URL scheme you are using. Have you double-double (double!) checked that the bundle identifier and URL scheme match? Have you verified that your app can be launched with the URL from Safari?

answered Dec 14 '16 at 10:05

Kasper Munck

4,173
2
27
50

I am having the kind of same error as the author of this article here. I tribble checked my bundle_identifier und url scheme and everything... still... I am getting an -50 error (didn't find a proper one from the link you posted :( ) Do you have any other ideas for me? – Georg Nov 20 '18 at 10:42
"double-double (double!) checked that the bundle identifier and URL scheme match" (c) – hbk Mar 31 '20 at 13:44

score 5 · Answer 2 · answered Mar 09 '17 at 13:33

5

URL scheme should added to the main app's info.plist, not the widget's.

answered Mar 09 '17 at 13:33

Eva Hsueh

61
1
5

score 4 · Answer 3 · answered Feb 16 '17 at 05:50

To open the Containing App from Todays Extension:

let myAppUrl = URL(string: "main-screen:")!
extensionContext?.open(myAppUrl, completionHandler: { (success) in
    if (!success) {
        print("error: failed to open app from Today Extension")
    }
})

You also need to add the following lines to the application's info.plist (open as a source code):

    <key>CFBundleURLTypes</key>
    <array>
        <dict>
            <key>CFBundleURLName</key>
            <string>com.mikitamanko.bubblewrap</string>
            <key>CFBundleURLSchemes</key>
            <array>
                <string>main-screen</string>
            </array>
        </dict>
    </array>

right after the

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE plist PUBLIC "-//Apple//DTD PLIST 1.0//EN" "http://www.apple.com/DTDs/PropertyList-1.0.dtd">
<plist version="1.0">
<dict>

Here's the complete guide how to open the app or share Users Defaults with Extension and the containing app.

score 0 · Answer 4 · answered Aug 03 '20 at 15:52

Also you should check if you are using any not allowed character for your url scheme. Maybe it is not your case but I was using this and it was wrong:

my_AppName

instead this finally worked :)

myAppName

as said here, the scheme must begin with alphanumeric character and it can contain only alphanumeric characters, +, - and .

NSWidgetExtensionContext openURL Swift

4 Answers4

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