How to get everything from the list except the first element using list slicing

Question

So I have something that I am parsing, however here is an example of what I would like to do:

list = ['A', 'B', 'C']

And using list slicing have it return to me everything but the first index. So in this case:

['B', 'C']

I have been messing with stuff like list[:-1], list[::-1], list[0:-1], etc. But I can't seem to be able to find this out.

What I am actual doing is: * I have a error message that has a error code in the beginning such as:

['226', 'Transfer', 'Complete']

and I want to just display Transfer Complete on a popup widget. Of course I am casting to a string.

Thank you for all help, and if answer differs via Python 2.7.x and Python 3.x.x Please answer for both versions.

Thanks, looked a lot around stackoverflow and python tutorials couldn't really quite get what I was looking for. Thanks for your help!

@juanpa.arrivillaga, thanks that worked! Really appreciate it! — Omid CompSCI, Nov 05 '16 at 21:23
@cricket_007 is that an alternative of doing .split( " ") [1:]? — Omid CompSCI, Nov 05 '16 at 21:25
Split returns a list. Slicing returns a list. String Joining returns a string, so no, it's the inverse, not alternative — OneCricketeer, Nov 05 '16 at 21:29
@cricket_007 oh sweet I think that is exactly what i am looking for let me try it! — Omid CompSCI, Nov 05 '16 at 21:30

score 161 · Accepted Answer · answered Nov 05 '16 at 21:22

161

You can just do [1:]. This will work on both versions.

answered Nov 05 '16 at 21:22

score 56 · Answer 2 · edited Nov 06 '16 at 04:40

56

It can be done like this:

list[1:]

edited Nov 06 '16 at 04:40

pzp

answered Nov 05 '16 at 21:23

2 Answers2