I have a URL like this:
http://www.chalklit.in/post.html?chapter=V-Maths-Addition%20&%20Subtraction&post=394
How to get the value of parameter of chapter and post?
My URL contains '&' in the value of chapter parameter.
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Vadim Kotov
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Shubham Chauhan
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If your parameter have space or other white space character, then use POST method for send data. – Chirag Savsani Nov 07 '16 at 13:22
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There are few class for parsing URI in java or android framework itself, what had you tried so far? – Selvin Nov 07 '16 at 13:22
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1`Uri.parse().getQueryParameter()` – Blackbelt Nov 07 '16 at 13:23
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1"My url contains '&' in the value of chapter parameter." Then it is broken. `&` needs to be url-encoded. AFAIK that should be %26 or something around that. – Fildor Nov 07 '16 at 13:26
1 Answers
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You can use the Uri class in Android to do this; https://developer.android.com/reference/android/net/Uri.html
Uri uri = Uri.parse("http://www.chalklit.in/post.html?chapter=V-Maths-Addition%20&%20Subtraction&post=394");
String server = uri.getAuthority();
String path = uri.getPath();
String protocol = uri.getScheme();
Set<String> args = uri.getQueryParameterNames();
Then you can even get a specific element from the query parameters as such;
String chapter = uri.getQueryParameter("chapter"); //will return "V-Maths-Addition "
jason.kaisersmith
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1See comment above. You need to escape / url-encode `&`. It cannot be in the value. Where do you get that URL from. Do you have control over its construction? – Fildor Nov 07 '16 at 13:28
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1Looks like your & is not correctly encoded, it should be %26 for an & otherwise it will be interpreted as a separator of parameters. – jason.kaisersmith Nov 07 '16 at 13:30
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Beware that parameters of url with fragment (with # in it after a main part) not going to be parsed. One of the solutions for it is to replace "#" with "?" – Johnny Five Jun 19 '20 at 11:22