Is it possible to use retrofit without model class?

Question

i have problem to use model class in retrofit lib. A backend side field name has changed.

Is it possible to get response without model class?

refer http://stackoverflow.com/questions/37119905/retrofit-2-without-model-class — sasikumar, Nov 09 '16 at 09:18
If your backend is not reliable, then Retrofit may be the wrong library. Just stick with OkHttp — OneCricketeer, Nov 09 '16 at 09:23
Question doesn't make sens ... *Retrofit - **Type-safe** HTTP client for Android and Java by Square, Inc.* ... *Is it possible to get response without model class?* **then what you wana get at the end?** — Selvin, Nov 09 '16 at 09:24
@Selvin OP probably means just get raw strings, not something that will need to be mapped to a user defined POJO class — OneCricketeer, Nov 09 '16 at 09:27
... or maybe some dictionaries(HashMap) ... but as you wrote - why Retrofit then? ... still *OP probably means just get raw strings* ... well without posting this in the question it's only blind guess — Selvin, Nov 09 '16 at 09:28

score 19 · Answer 1 · answered Nov 09 '16 at 09:25

Yes, you can.

@POST("url")

 Call<JsonObject> register(@Query("name") String name,

                           @Query("password") String password);

Just write JsonArray or JsonObject according to your response instead of Model class.

Then, get data from JsonObject or JsonArray which you get in response as below

Call<JsonObject> call = application.getServiceLink().register();

call.enqueue(new Callback<JsonObject>() {
            @Override
            public void onResponse(Call<JsonObject> call, Response<JsonObject> response) {
                JsonObject object = response.body();
                //parse object 
            }

            @Override
            public void onFailure(Call<JsonObject> call, Throwable t) {

            }
        });

Hi , thank you for your response ,i had illegal argument Exception,can please tell me how to define retrofit.It not working in GET method — Vadivel, Nov 09 '16 at 09:31

Malcolm · Answer 2 · 2016-11-09T09:32:50.530

4

It is perfectly possible using different return values. I assume that you currently use Gson to deserialize JSON responses, and they get converted to the actual class. However, you may choose to convert the returned response to JsonElement (or some more specific JSON class), in that case you will get a JSON item which you can manipulate as you wish to. Something like:

@GET("url")
Call<JsonElement> apiCall();

edited Nov 09 '16 at 09:32

answered Nov 09 '16 at 09:21

Malcolm

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I don't think the converter is the issue. OP says a JSON field has changed, therefore invalidating the potential JSON annotations that Jackson or Gson would provide – OneCricketeer Nov 09 '16 at 09:24
Thanks Mr.Malcolm ,i Fixed the issue – Vadivel Nov 09 '16 at 09:55
@Vadivel You can upvote the answers that helped you, and don't forget to accept the one that helped you most. – Malcolm Nov 09 '16 at 09:56
I'm so sorry Mr.Malcolm, i'm not reach that much of reputation, – Vadivel Nov 09 '16 at 09:58
@Vadivel You have enough reputation now, you need only 15 points to do that. – Malcolm Nov 09 '16 at 10:01

score 3 · Answer 3 · answered Nov 23 '16 at 14:08

@Vadivel here it is the version of GET based on @chetan work:

@GET("http://your.api.url")
Call<JsonObject> getGenericJSON();

Call<JsonObject> call = api.getGenericJSON();
call.enqueue(new Callback<JsonObject>() {

    @Override
    public void onResponse(Call<JsonObject> call, Response<JsonObject> response) {
        if (response.isSuccessful() && response.body() != null) {
            Log.d(TAG, response.body().toString());
        } else {
            Log.e(TAG, "Error in getGenericJson:" + response.code() + " " + response.message());
        }
    }

    @Override
    public void onFailure(Call<JsonObject> call, Throwable t) {
        Log.e(TAG, "Response Error");
    }
});

score 2 · Answer 4 · answered Nov 09 '16 at 09:18

2

Is it possible to get response without model class

If I get you right - sure. You do not have to make response JSON auto-converted. You can do this easily by hand if needed, by retrieving raw response. Once you got that you can do whatever you need.

answered Nov 09 '16 at 09:18

Marcin Orlowski

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@Vadivel, if you fixed this issue, could you give some answers corresponding to your problems and how you fixed it. I am facing same issue like you. Thanks. – ZarNi Myo Sett Win Mar 12 '18 at 08:28
I just refer first answer post of this question. just use instead of Call to Call – Vadivel Mar 12 '18 at 09:09
@Vadivel,it is ok now .Thanks. – ZarNi Myo Sett Win Mar 12 '18 at 09:35

score 0 · Answer 5 · answered Nov 09 '16 at 15:09

0

You can simply "rename" field on your side using

@SerializedName("newFieldName")
SomeClass oldField;

answered Nov 09 '16 at 15:09

Sviatoslav Melnychenko

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Is it possible to use retrofit without model class?

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