Syntax for creating a Variable of Sub Class

Question

template <class T>
class Stack
{
private:
    template <class L>
    class List
    {
    public:
        class Node
        {
        public:
            L data;
            Node* next;
        };
    Node* head;
};
    List<T> list;
public:
};

I want to create a variable of class Node in Stack class and I'm using this syntax

 List<T>::Node version;

But Visual Studio gives it at as syntax error. Please help me

Possible duplicate of [Where and why do I have to put the "template" and "typename" keywords?](http://stackoverflow.com/questions/610245/where-and-why-do-i-have-to-put-the-template-and-typename-keywords) — , Nov 10 '16 at 03:59
Because `List::Node` is dependent on template parameter `T`, the standards says we have to use `typename` to tell the compiler `List::Node` is a name of type (not other things like name of member). See the link posted by @NickyC for details. — songyuanyao, Nov 10 '16 at 04:03

score 0 · Answer 1 · answered Nov 10 '16 at 05:06

0

As @songyuanyao said Try typename List<T>::Node version; to create a variable of class Node in Stack class

answered Nov 10 '16 at 05:06

Real73

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Syntax for creating a Variable of Sub Class

1 Answers1