Counting specific lines in a log file

Question

I have a log file containing more than 100000 lines similar to the following

2016-11-08 17:04:01|x.x.x.x|xxxxxxxxxxxxx|x.x.x.x|1002|xxxx|xxxxxx|1|2|https://xxxxxxxxx/xxxxxxx/xxxxxxx/xxxxxx{"status":500,"body":""}
2016-11-08 17:04:02|x.x.x.x|xxxxxxxxxxxxx|x.x.x.x|1003|xxxx|xxxxxx|1|2|https://xxxxxxxxx/xxxxxxx/xxxxxxx/xxxxxx{"status":400,"body":""}

Please help me to write a script that will return a count of lines only with "status":500.

google `grep` and write your script – jblixr Nov 10 '16 at 04:25 — jblixr, Nov 10 '16 at 04:25
`grep -c "\"status\":500" filename` – Thirupathi Thangavel Nov 10 '16 at 04:26 — Thirupathi Thangavel, Nov 10 '16 at 04:26

score 1 · Accepted Answer · answered Nov 10 '16 at 06:04

1

Try grep -c "\"status\":500 /path/to/logfile.dat

answered Nov 10 '16 at 06:04

oliver

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why struggle when you can use single quotes? `grep -c '"status":500'` – Sundeep Nov 10 '16 at 08:24

Counting specific lines in a log file

1 Answers1