Most efficient way to make the first character of a String lower case?

Question

What is the most efficient way to make the first character of a String lower case?

I can think of a number of ways to do this:

Using charAt() with substring()

String input   = "SomeInputString";
String output  = Character.toLowerCase(input.charAt(0)) +
                   (input.length() > 1 ? input.substring(1) : "");

Or using a char array

 String input  = "SomeInputString";
 char c[]      = input.toCharArray();
 c[0]          = Character.toLowerCase(c[0]);
 String output = new String(c);

---

I am sure there are many other great ways to achieve this. What do you recommend?

Answer 1

I tested the promising approaches using JMH. Full benchmark code.

Assumption during the tests (to avoid checking the corner cases every time): the input String length is always greater than 1.

Results

Benchmark           Mode  Cnt         Score        Error  Units
MyBenchmark.test1  thrpt   20  10463220.493 ± 288805.068  ops/s
MyBenchmark.test2  thrpt   20  14730158.709 ± 530444.444  ops/s
MyBenchmark.test3  thrpt   20  16079551.751 ±  56884.357  ops/s
MyBenchmark.test4  thrpt   20   9762578.446 ± 584316.582  ops/s
MyBenchmark.test5  thrpt   20   6093216.066 ± 180062.872  ops/s
MyBenchmark.test6  thrpt   20   2104102.578 ±  18705.805  ops/s

The score are operations per second, the more the better.

Tests

1. test1 was first Andy's and Hllink's approach:

    string = Character.toLowerCase(string.charAt(0)) + string.substring(1);
   

2. test2 was second Andy's approach. It is also Introspector.decapitalize() suggested by Daniel, but without two if statements. First if was removed because of the testing assumption. The second one was removed, because it was violating correctness (i.e. input "HI" would return "HI"). This was almost the fastest.

    char c[] = string.toCharArray();
    c[0] = Character.toLowerCase(c[0]);
    string = new String(c);
   

3. test3 was a modification of test2, but instead of Character.toLowerCase(), I was adding 32, which works correctly if and only if the string is in ASCII. This was the fastest. c[0] |= ' ' from Mike's comment gave the same performance.

    char c[] = string.toCharArray();
    c[0] += 32;
    string = new String(c);
   

4. test4 used StringBuilder.

    StringBuilder sb = new StringBuilder(string);
    sb.setCharAt(0, Character.toLowerCase(sb.charAt(0)));
    string = sb.toString();
   

5. test5 used two substring() calls.

    string = string.substring(0, 1).toLowerCase() + string.substring(1);
   

6. test6 uses reflection to change char value[] directly in String. This was the slowest.

    try {
        Field field = String.class.getDeclaredField("value");
        field.setAccessible(true);
        char[] value = (char[]) field.get(string);
        value[0] = Character.toLowerCase(value[0]);
    } catch (IllegalAccessException e) {
        e.printStackTrace();
    } catch (NoSuchFieldException e) {
        e.printStackTrace();
    }
   

Conclusions

If the String length is always greater than 0, use test2.

If not, we have to check the corner cases:

public static String decapitalize(String string) {
    if (string == null || string.length() == 0) {
        return string;
    }

    char c[] = string.toCharArray();
    c[0] = Character.toLowerCase(c[0]);

    return new String(c);
}

If you are sure that your text will be always in ASCII and you are looking for extreme performance because you found this code in the bottleneck, use test3.

Answer 2

I came across a nice alternative if you don't want to use a third-party library:

import java.beans.Introspector;

Assert.assertEquals("someInputString", Introspector.decapitalize("SomeInputString"));

Answer 3

When it comes to string manipulation take a look to Jakarta Commons Lang StringUtils.

Answer 4

If you want to use Apache Commons you can do the following:

import org.apache.commons.lang3.text.WordUtils;
[...] 
String s = "SomeString"; 
String firstLower = WordUtils.uncapitalize(s);

Result: someString

Answer 5

Despite a char oriented approach I would suggest a String oriented solution. String.toLowerCase is Locale specific, so I would take this issue into account. String.toLowerCase is to prefer for lower-caseing according to Character.toLowerCase. Also a char oriented solution is not full unicode compatible, because Character.toLowerCase cannot handle supplementary characters.

public static final String uncapitalize(final String originalStr,
            final Locale locale) {
        final int splitIndex = 1;
        final String result;
        if (originalStr.isEmpty()) {
        result = originalStr;
        } else {
        final String first = originalStr.substring(0, splitIndex).toLowerCase(
                locale);
        final String rest = originalStr.substring(splitIndex);
        final StringBuilder uncapStr = new StringBuilder(first).append(rest);
        result = uncapStr.toString();
        }
        return result;
    }

UPDATE: As an example how important the locale setting is let us lowercase I in turkish and german:

System.out.println(uncapitalize("I", new Locale("TR","tr")));
System.out.println(uncapitalize("I", new Locale("DE","de")));

will output two different results:

ı

i

Answer 6

Strings in Java are immutable, so either way a new string will be created.

Your first example will probably be slightly more efficient because it only needs to create a new string and not a temporary character array.

Answer 7

A very short and simple static method to archive what you want:

public static String decapitalizeString(String string) {
    return string == null || string.isEmpty() ? "" : Character.toLowerCase(string.charAt(0)) + string.substring(1);
}

Answer 8

val str = "Hello"
s"${str.head.toLower}${str.tail}"

Result:

res4: String = hello

Answer 9

If what you need is very simple (eg. java class names, no locales), you can also use the CaseFormat class in the Google Guava library.

String converted = CaseFormat.UPPER_CAMEL.to(CaseFormat.LOWER_CAMEL, "FooBar");
assertEquals("fooBar", converted);

Or you can prepare and reuse a converter object, which could be more efficient.

Converter<String, String> converter=
    CaseFormat.UPPER_CAMEL.converterTo(CaseFormat.LOWER_CAMEL);

assertEquals("fooBar", converter.convert("FooBar"));

To better understand philosophy of the Google Guava string manipulation, check out this wiki page.

Answer 10

String testString = "SomeInputString";
String firstLetter = testString.substring(0,1).toLowerCase();
String restLetters = testString.substring(1);
String resultString = firstLetter + restLetters;

Answer 11

I have come accross this only today. Tried to do it myself in the most pedestrian way. That took one line, tho longish. Here goes

String str = "TaxoRank"; 

System.out.println(" Before str = " + str); 

str = str.replaceFirst(str.substring(0,1), str.substring(0,1).toLowerCase());

System.out.println(" After str = " + str);

Gives:

Before str = TaxoRanks

After str = taxoRanks