Why this regexp returns false for
/[\\]/igm.test('asdasdasd\asdasd');
and true for
/[\\]/igm.test('asdasdasd\\asdasd');
and when I try this it gives error, why..?
/[\\]/igm.test('abc\xyz');
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Mr. A
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1On which platform is this? – Murat Karagöz Nov 10 '16 at 13:27
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`\a` is a character, `\\a` is the character ` \ ` followed by `a` . As for the error, I do not know. – Lupu Silviu Nov 10 '16 at 13:27
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I am executing it on chrome console – Mr. A Nov 10 '16 at 13:28
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@LupuSilviu I dont understand why "\a" will be a character as "a" is not a notation in regex – Mr. A Nov 10 '16 at 13:31
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@Mr.A `\a matches the bell character (ASCII 7)`. This is that regex translates \a to. – Lupu Silviu Nov 10 '16 at 13:33
1 Answers
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\x is a character escape for an ASCII character, where the next two characters must be hexidecimal digits. So, \xyz is invalid because y and z aren't hex digits.
JohnnyHK
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