c++ Void function interaction problems

Question

I have a possibly simple question Is it possible to have to that void1 and void2 interact with eachother? Here's what i mean :

void void1(){
   void2();
}
void void2(){
   void1();
}

I mainly asked this because i have a school project and i'm kind of in a rush. Thank you

`while(true);` is an interesting alternative approach to this. — skypjack, Nov 11 '16 at 22:23
Oh yeah i forgot that. I just made a mistake in the example though. — BakonBot, Nov 11 '16 at 22:23
@skypjack it's a *better* approach, since it won't lead to a stack overflow. But I suspect there's some code missing from this example that breaks out of the infinite loop. — Mark Ransom, Nov 11 '16 at 22:25
In this code `void void2` would need to be predeclared at the beginning, like `void void2();`. That way it can be called in `void1`, even though its definition comes only after that of `void1` in the code. — tmlen, Nov 11 '16 at 22:28

score 0 · Answer 1 · answered Nov 11 '16 at 22:26

0

In order to call one function from the other, you have to provide a declaration of the function before you try to use it.

void void2();

void void1(){
   void2();
}
void void2(){
   void1();
}

answered Nov 11 '16 at 22:26

Mark Ransom

so calling one of them is a behavior of an infinite loop – Raindrop7 Nov 11 '16 at 22:42

1 Answers1