api.LookupUser([u.user_id for u in userlist])

Question

With Python, I have a userlist with a bunch of userids [1234,321,1203,2348,45955] and so forth. I'm trying to pass the userids into the api.LookupUser function.

This function usually takes one user_id at a time. For example, api.LookupUser(user_id=123)

Is there an easy way to pass each value from the userlist into the function?

@cricket_007, I'm not too sure. I'd like to test both ways to find out. — New, Nov 12 '16 at 04:36

OneCricketeer · Accepted Answer · 2016-11-12T04:50:02.617

0

I think you are looking for this

users = (api.LookupUser(user_id=x) for x in userids)

Or, at least in Python3,

users = map(api.LookupUser, userids)

And these return a generator, so you'll call next(users) to get the next value. I believe this also delays the API call, so you aren't getting all the users at once and bogging down the API

So, looping though that generator

for u in users:
    print(u)

edited Nov 12 '16 at 04:50

answered Nov 12 '16 at 04:37

OneCricketeer

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Yes, I think that's it. I got this return generator - at 0x039EB878> How do you call next(users)? – New Nov 12 '16 at 04:41
Right. As I said, call next on that – OneCricketeer Nov 12 '16 at 04:42
Literally, just that... http://stackoverflow.com/questions/1756096/understanding-generators-in-python – OneCricketeer Nov 12 '16 at 04:43
Would that mean all of this goes into a loop? – New Nov 12 '16 at 04:43
Probably, yes, but only when you actually need all of the user objects. Say you have a website or other GUI, and a table, you'd only display like 10 users at a time – OneCricketeer Nov 12 '16 at 04:45
I'm planning on having it loop through all of the users. Would it be like this? for x in userids: users = (api.LookupUser(user_id=x) for x in userids) next(users) – New Nov 12 '16 at 04:47
Nope, because that is regenerating the generator within the loop and only getting the first user – OneCricketeer Nov 12 '16 at 04:50

api.LookupUser([u.user_id for u in userlist])

1 Answers1