infile=open("Integers.txt", "r")
ListIntegers=infile.readline().strip("\n").split(";")
def avgFirstThreeDigits(mylist):
list=[]
for i in range(0,len(mylist)):
sumFirstThreeDigits=(int(mylist[i][0])+int(mylist[i][1])+int(mylist[i][2]))
avg=sumFirstThreeDigits/3
list.append(avg)
print(list[::-1])
avgFirstThreeDigits(ListIntegers)
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(Sorry for the code) – Atakan Ak Nov 14 '16 at 19:21
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Select the code and press "ctrl+k" to format it. – Brian Rodriguez Nov 14 '16 at 19:22
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don't be sorry. edit and format it correctly. – njzk2 Nov 14 '16 at 19:22
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also, consider using the "search" feature. – njzk2 Nov 14 '16 at 19:23
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1@AtakanAk. What's wrong with `[::-1]`? Is this a homework question? – ekhumoro Nov 14 '16 at 19:27
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Ok thanks. Yes its a homework question we can't use [::-1] – Atakan Ak Nov 14 '16 at 19:38
2 Answers
1
You can manually reverse a list with the following:
a = ['a', 'b', 'c', 'd']
b = [a[len(a) - i - 1] for i in range(len(a))]
>>> b
>>> ['d', 'c', 'b', 'a']
Jeff Mandell
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If you just want to get a list of tuples/vectors averages, you can just do something like this:
list_averages = [(sum(v3) / len(v3)) for v3 in list_integers]
Or just using another of the multiple ways to calculate the arithmetic mean average will do
About an alternative to [::-1], you can just use list.reverse
But be aware list.reverse will modify in place, if you don't want to you could use list(reversed(list_averages)). In any case, I don't know why you don't want to use [::-1], that one is a pretty fast choice.
