Convert IEnumerable to multidimensional array

Question

Is there a pretty way I can change my previous code:

char[][] board = Enumerable.Repeat(Enumerable.Repeat('-', 7).ToArray(), 7).ToArray();

so that it uses multidimensional arrays instead?

E.g.

char[,] = ...

the array should represent this kind of data structure:

-------
-------
-------
-------
-------
-------
-------

Possible duplicate of [How to convert list of arrays into a multidimensional array](http://stackoverflow.com/questions/9774901/how-to-convert-list-of-arrays-into-a-multidimensional-array) — Nkosi, Nov 17 '16 at 00:38
Here is another one http://stackoverflow.com/a/1814063/5233410 — Nkosi, Nov 17 '16 at 00:40
@KirkWoll the former isn't working, when I try to assign `board[5][2] = '*'` it seems to assign in every row, rather than just the 6th. — theonlygusti, Nov 17 '16 at 00:45
@KirkWoll what? That is how I have always assigned to 2d arrays (well, "jagged" arrays) in every other language I have used — theonlygusti, Nov 17 '16 at 00:46
@theonlygusti, I have no idea what you are talking about. `x[a][b] = y` will only ever assign a single element in every language I've ever seen. — Kirk Woll, Nov 17 '16 at 00:47
@theonlygusti, please provide an MCVE that illustrates the behavior you describe. As I can guarantee what you are describing is not what happens in C#. — Kirk Woll, Nov 17 '16 at 00:49
@KirkWoll http://stackoverflow.com/questions/40644966/how-to-assign-to-a-jagged-array — theonlygusti, Nov 17 '16 at 00:49
Please provide a console application with a `Main` method that demonstrates the behavior you describe. I looked at the question you just linked to and that's not going to work -- too much hand waving. — Kirk Woll, Nov 17 '16 at 00:50
Yes, do whatever you can to provide a short program that demonstrates the problem and I guarantee you will get an exponentially more useful response. — Kirk Woll, Nov 17 '16 at 00:53
@theonlygusti and above all, make sure your example actually *compiles*! :) — Kirk Woll, Nov 17 '16 at 00:53

score 1 · Answer 1 · answered Nov 17 '16 at 01:43

1

            char[,] board = new char[7,7];

            for(int i =0; i< 7; i++)
            {
                for (int k = 0; k < 7; k++)
                {
                    board[i,k] = '-';
                }
            }

Are you looking for this?

answered Nov 17 '16 at 01:43

Swetha

457
4
7

1

Yes, but IMO that is really ugly. – theonlygusti Nov 17 '16 at 07:22
Well this is the standard way of initialising a 2d array:) – Swetha Nov 17 '16 at 13:00
may be you can put this in an initialiser method and then call it with a parameter – Swetha Nov 17 '16 at 13:01

Convert IEnumerable to multidimensional array

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