Get filename from each folder (like nested) using PHP

Question

My directory Structure is like

car_brands/AAA/alto.php
car_brands/BBB/figo.php
car_brands/CCC/beat.php

PHP Code

     <?php   
             $dir = "Car_Brands";  
             $dh  = opendir($dir);  
             while (false !== ($filename = readdir($dh))) 
             {     
              $files[] = $filename;  
              }  
              natcasesort($files); 
               foreach ($files as $file) 
                {
                if($file!='.' && $file!='..')   
                {  
                 echo $file;
                } 
               }    
?>

Like I want

<a href="Car_Brands/<?php echo $file; ?>/"here i want filename of particular folder"" class="btn btn-red" style="width:180px;height:50px;"><br/><?php echo $file; ?><br/></a>

By This code I can get folders under car_brands.like AAA,BBB,CCC but how can get the php filename under each folder in single foreach loop is there any easy way to do this.

Possible duplicate of [List all the files and folders in a Directory with PHP recursive function](http://stackoverflow.com/questions/24783862/list-all-the-files-and-folders-in-a-directory-with-php-recursive-function) — Manh Nguyen, Nov 19 '16 at 06:27
If I use tht its showing error like : Call to undefined function getDirContents() — Kavya Shree, Nov 19 '16 at 06:35
In that question they get all path and filenames but I want foldername alone in one variable array and filename inside specific folder in seperate variable — Kavya Shree, Nov 19 '16 at 06:42

score 4 · Answer 1 · answered Nov 19 '16 at 07:14

<?php 
               foreach ($files as $file) 
                {
                if($file!='.' && $file!='..')   
                {
                $dir_path="Car_Brands/".$file."/";  
  $files_names = implode("",preg_grep('~\.(php)$~', scandir($dir_path)));
                    ?>        
               <div class="col-md-2"><br/>      
               <a href="Car_Brands/<?php echo $file; ?>/<?php 
          echo $files_names; ?>" class="btn btn-red" style="width:180px;height:50px;"><br/><?php echo $file; ?><br/></a>      </div>
               <?php 
               } 
               }    
                ?>

This is how I tried now its working thanks for everyone who helped me with new ideas

Kamrul Khan · Accepted Answer · 2016-11-19T07:11:37.047

you can use scandir to get the list of all files in a given directory.

So, your code be changed like this:

         $dir = "Car_Brands";  
         $dh  = opendir($dir);  
         while (false !== ($subdir = readdir($dh))) 
         {   
             $fileList = scandir($dir.'/'.$subdir);
             $files[] = $fileList[2];  
         }  
         natcasesort($files); 
         foreach ($files as $file) 
         {
            if($file!='.' && $file!='..')   
            {  
                 echo $file;
            } 
         }

scandir() returns an array that contains the list of all the files in the given directory. If you are in linux server and you are sure each of your directory has one file only, you should get your file name from the 3rd index of the Array, which is $fileList[2] in our case. It is the 3rd index cause if you do a var dump of the array that scandir() returns you will see something like below:

Array
(
    [0] => .
    [1] => ..
    [2] => alto.php
)

I would recommend you to do a print_r($fileList) within your loop, that will give you a better idea on what index to look at.

Update

You can also use glob. In that case your code will look like the below:

         $dir = "Car_Brands";
         $dh  = opendir($dir);
         while (false !== ($dirname = readdir($dh)))
         {
             if ($dirname == '..' || $dirname == '.') {
                 continue;
             }
             $subdir = $dir.'/'.$dirname.'/';
             $ext = '*.php';
             $fileList = glob($subdir.$ext);
             if (!empty($fileList)) {
                 $files[] = $fileList[0];
                 // The above line will return the whole path. (eg. car_brands/AAA/alto.php)
                 // if you want the file name only (eg. alto.php) use the below line instead
                 // $files[] = str_replace($subdir, '', $fileList[0]);
             }
         }
         natcasesort($files);
         foreach ($files as $file)
         {
             echo $file;
         }

I want path like this here it echo altoalto_new.php .How can i split alto in one variable and alto_new.php in another variable — Kavya Shree, Nov 19 '16 at 06:47
Array ( [0] => . [1] => .. [2] => images [3] => vista.php ) its just return this only — Kavya Shree, Nov 19 '16 at 06:49
Very simple user.If I give one folder like('alto') I just want in return as alto_new.php alone wht can i do — Kavya Shree, Nov 19 '16 at 07:04

Get filename from each folder (like nested) using PHP

2 Answers2