How can I store a 16 byte number into memory in assembly?

Question

section .bss
   length equ 16
   number: resb length

This works only with 64 bits:

mov qword[number], 43271

This is represented of only 8 byte (64 bit). I need to store values in memory in 128 bit, but I've no idea how I can do that.

Thanks

Or use SSE loads/stores (e.g. [`MOVDQU`](http://www.felixcloutier.com/x86/MOVDQU.html)). — Paul R, Nov 19 '16 at 22:11
Second that. Like `mov qword[number], 43271` + `mov qword[number+8], 54382`. — zx485, Nov 19 '16 at 22:11
@zx485: sure - it would be a very long instruction if it did. — Paul R, Nov 19 '16 at 22:13
According to this link: http://stackoverflow.com/questions/12063840/what-are-the-sizes-of-tword-oword-and-yword-operands Why doesn't works this command? `number do 11` It returns: "Integer supplied to a DT, DO or DY instruction?" — Davide, Nov 20 '16 at 13:03

score 3 · Answer 1 · answered Nov 19 '16 at 22:25

3

The standard approach is to use two store instructions, one for each half:

mov qword [number], 1234
mov qword [number+8], 4567

answered Nov 19 '16 at 22:25

fuz

1 Answers1