Python List of dates between x and z (dd//mm/year)

Question

from datetime import date, timedelta as td

d1 = date(1980, 1, 1)
d2 = date(2000, 1, 1)

delta = d2 - d1

for i in range(delta.days + 1):
    print d1 + td(days=i)

How would I make it so it displays it in this form: dd/mm/yy Thanks :)

score 2 · Answer 1 · answered Nov 20 '16 at 16:20

2

Use strftime:

print your_date.strftime("%d/%m/%y")

answered Nov 20 '16 at 16:20

ForceBru

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What about for the full year like 1990? It only shows 90 but other than that its fine – smye Nov 20 '16 at 16:25
1

@smye, `yy` in the format normally means '_year without century as a zero-padded decimal number_'. Have you checked the link I've given in my answer? – ForceBru Nov 20 '16 at 16:26
Thank you for this, didn't realise it was hyperlinked ;P – smye Nov 20 '16 at 16:46

score 1 · Accepted Answer · answered Nov 20 '16 at 16:28

Simply add this to your Print statement:

from datetime import date, timedelta as td

d1 = date(1980, 1, 1)
d2 = date(2000, 1, 1)

delta = d2 - d1

for i in range(delta.days + 1):
    print ((d1 + td(days=i)).strftime("%d/%m/%Y"))

Output: ...

Thnk you very much. Both answers very useful. I needed a captical Y not a y. — smye, Nov 20 '16 at 16:38
I know as 2000 on wards can look confusing if only 00.And welcome to Stack Overflow! If this helped you, you can tell the community so by voting the answer! :) — Taufiq Rahman, Nov 20 '16 at 16:40
Thank you for the welcome. Both solutions worked but I approved yours since gave an example of output too. Both did same thing so thank you both — smye, Nov 20 '16 at 16:45

Python List of dates between x and z (dd//mm/year)

2 Answers2