6

Ok, so i have this template class, which is kinda like one-way list.

template <typename T> List

and it have this inside function print

public:
void Print();

which, as you can guess, prints the list contents from begining to end; However, as template can take classes as T, one can imagine, that i would need different implementations of Print() for that very cases. For example, I have another class Point

class Point{
 private:
  int x, y;
 public:
  int getX();
  int getY();
}

so i want Print specifically designed for Points. I tried this:

void List<Point>::Print();

but compiler tells me

prototype for void List<Point> Print() doesn match any in class List<Point>

though

candidates are: from List<T> [with T = Point] void List<Point>::Print()

For me it seems like the same fucntion. What's wrong? And how do I write T-specific template class functions?

Yury Elburikh
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2 Answers2

9

You use explicit template specialization to specialize behaviour of Print for specific types.

For example, for Point:

template <> // No template arguments here !
void List<Point>::Print() // explicitly name what type to specialize
{
  //code for specific Point Print behaviour..
}
Hatted Rooster
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1

However, as template can take classes as T, one can imagine, that i would need different implementations of Print() for that very cases

Not at all. You can have a single implementation of Print for every type of object - this is why templates are powerful.

One way to do what you want would be to define the stream operator << in Point, and have a generic Print() method in List. This makes Print available to more than just Point.

More generality ftw.

aspen100
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    Hmm, this approach I like a whole lot more, however, for this project I have to use Point provided without any modifications to it – Yury Elburikh Nov 21 '16 at 15:15